-8x + 3x2 - 3
3(x + 1)(x + 2)
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
3x2 + 27x +60
-8x + 3x2 - 3
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
(x + 2y)(3x + 8y)
(x + 1)(3x + 5)
Just looking at it, one factor is 3.
3x2+7-6 = (3x-2)(x+3) when factored
(3x+1)(x+2)
3(x + 1)(x + 2)
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
x3 - 3x2 + x - 3 = (x - 3)(x2 + 1)
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms