If the question is to factor the problem, 3x2 - 6x + 9, then it can not be factored.
If the question is to solve for x, assuming the equation is equal to zero, then use the quadratic formula with,
a= 3
b= -6
c= 9
Then, 6 +- sqrt[36 - 4(3)(9)], all divided by 2(3)
6 +- sqrt[36 - 108] divided by 6
[6 +- sqrt(-72)] / 6
To reduce a negative square root, first pull out the negative one by using i, then find the perfect square in 72, which is 36, so the equation becomes:
6+- 6isqrt(2) / 6
Reduce the fraction and cancel the sixes
1 + i sqrt(2) AND 1 - i sqrt(2)
(x2 + 26x +) : syntax error.x2 + 26x
.740
8x + 26x - 7 = 34x - 7 = (√34x)2 - (√7)2 = √34x - √7)(√34x + √7)
2(5x - 1)(3x - 2)
The answer to this equation would be 5. This is a math problem.
(x2 + 26x +) : syntax error.x2 + 26x
26x + 9 = 699Subtract 9 from each side:26x = 690Divide each side by 26 :x = 690/26 = 26 and 14/690 = 26 and 7/345 = 26.5385 (rounded)
x2 + 26x + 48 = (x + 24)(x + 2)
3x2+26x+16 When factorised: (3x+2)(x+8)
.740
8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)
8x + 26x - 7 = 34x - 7 = (√34x)2 - (√7)2 = √34x - √7)(√34x + √7)
x2+36x+120 (x+6)(x+20)
It is (3x-4)(5x-2) when factored
2(5x - 1)(3x - 2)
(5x + 6)(x + 4)
6xsquared minus 26x minus 5 over 3xsquared minus 15x