3y+6=y-2
We want to get all the y-terms on one sides and everything else on the other.
To do this we subtract y from both sides.
3y+6-y=y-2-y Adding like terms gives us (2y+6=-2)
Next, we subtract 6 from both sides.
[2y+6-6=(-2)-6] Adding like terms gives us [2y=-8] So y=(-4)
To double check plug y=(-4) into the beginning equations and see if they are equal.
3(-4)+6=(-6)
(-4)-2=(-6)
They are both equal so Y=(-4) is the correct answer
2x-11
y=+6 or y=-3
y=2
(1, 1)
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
2x-11
y=+6 or y=-3
Collect like terms: 2x + 3y + 3y - 5 - 6 2x + 6y - 11
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
y=2
10y= 6y+5+3y 10y=6+9y y=6
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
(1, 1)
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
They are parallel lines.
The answer is - not are : (5, 1).