4 feet high by 8 feet wide = diagonal of 107.28 inches.
diagonal lines can either increase or decrease height or width depending on their angle. If the diagonal line is closer to vertical it adds height and decreases width. If the diagonal line is closer to horizontal, it adds width and decreases height.
Width is 16.
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
When you have two numbers separated by the word "by", this means that those numbers are the width and height.
The diagonal length is about 18.44 inches.
diagonal lines can either increase or decrease height or width depending on their angle. If the diagonal line is closer to vertical it adds height and decreases width. If the diagonal line is closer to horizontal, it adds width and decreases height.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
Width is 16.
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
When you have two numbers separated by the word "by", this means that those numbers are the width and height.
The diagonal length is about 18.44 inches.
3.606 inches (rounded)
28 in
77 in
width, depth and height
Using Pythagoras' theorem the diagonal works out as 51 inches
length times width times height returns an answer in square inches, provided length, width and height are in inches. Example: 2(inches)*3(inches)*1(inches)=6(inches)*(inches)*(inches) =6(inches)^3=6 cubic inches