(6x + 1)(x + 13)
factor the trinomial 16x^2+24x+9
n(2n - 1)(2n + 7)
5a(a+2b+b²)
10 + 9x
-x(x - 99)(X + 27) x = 0, -27, 99
If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
6x(3x2 - x + 4)
You would factor 3a + 9b as: 3(a+3b)
That is 72-10-48-8 = 6/8 + 4 means 6/8 + 32/8 = 38/8
this problem cannot be factored
(x + 5)(x + 2)
(6x + 1)(x + 13)
-4
(x + 2)(x + 3)