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4x plus 6y equals 62 and -6x plus 6y equals -18?
4x+6y=62 -6x+6y=-18 what is the ordered pair
What is the solution to x if 4x-62(2x-4)?
There can be no solution since there is no equation (nor inequality) in the question.
If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
4x plus 6y equals 62 -6x plus 6y equals -18?
Subtracting gives: 10x = 80 so x = 8 and y = 5
What is the ordered pair of 4x plus 6y equals 62 -6x plus 6y equals -18?
4x + 6y = 62-6x + 6y = -18 Multiply this equation by -1 the result will be_______________4x + 6y = 626x - 6y = 18_______________ Equation 1 + Equation 2 the result will be10x = 80 ----> X=8Put the value of X in one of the Equations above to find the value of yand so Y=5
4x plus 6y equals 62 and -6x plus 6y equals -18?
4x+6y=62 -6x+6y=-18 what is the ordered pair
What is the variable in 18-4x equals 62?
x=11
What is the solution to x if 4x-62(2x-4)?
There can be no solution since there is no equation (nor inequality) in the question.
The perimeter of a rectangle is 62m the length is 7m more than twice the width find the dimensions?
Let the length be 2x+7 and the width be x: 2(2x+7+x) = 62 4x+14+2x = 62 4x+2x = 62-14 6x = 48 x = 8 Therefore: length = 23 meters and width = 8 meters
If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
The sum of three numbers is 62 The second number is equal to the first number diminished by 4 The third number is four times the first What are the numbers?
Suppose the first number is x. Then the second number is x-4 and the third is 4*x, or 4x So, x+(x-4)+4x = 62 ie 6x-4= 62 or 6x = 66 or x = 11. Then x-4 = 7 and 4x = 44 So the 3 numbers are 11, 7 and 44.
How do you solve the square root of 4x to the sixth power?
4x to the sixth can be expanded to (4x * 4x * 4x)(4x * 4x * 4x) or (4x to the third)(4x to the third) the square root of the above would be 4x to the third
What does 4x times 4x equal?
4x × 4x = (4x)² = 16x²
4x plus 6y equals 62 -6x plus 6y equals -18?
Subtracting gives: 10x = 80 so x = 8 and y = 5
What is the ordered pair of 4x plus 6y equals 62 -6x plus 6y equals -18?
4x + 6y = 62-6x + 6y = -18 Multiply this equation by -1 the result will be_______________4x + 6y = 626x - 6y = 18_______________ Equation 1 + Equation 2 the result will be10x = 80 ----> X=8Put the value of X in one of the Equations above to find the value of yand so Y=5
What is 4x plus 4x plus 4x plus 4x?
16x
Find the value of x: 2(4x + 4) = (4x - 12)?
2(4x + 4) = (4x - 12) 8x + 8 = 4x - 12 8x - 4x + 8 = 4x - 4x - 12 4x + 8 = -12 4x + 8 - 8 = -12 - 8 4x = -20 4x/4 = -20/4 x = -5
