(9 - y)(a + 5)
(9 - y)(a + 5)
9x + y = 22to solve for x-subtracy y from both sides --> 9x = 22 - ydivide by 9 on both sides --> x = (22/9) - (y/9)to solve for y - subtract 9x from both sides --> y = 22 - 9x
y+9=14 subtract 9 from each side to get y by itself y=5
-2-5
(9 - y)(a + 5)
(9 - y)(a + 5)
-9
9x + y = 22to solve for x-subtracy y from both sides --> 9x = 22 - ydivide by 9 on both sides --> x = (22/9) - (y/9)to solve for y - subtract 9x from both sides --> y = 22 - 9x
-13
y = -2/5
L.H.S.= R.H.S. 5+y=9 {we will shift 5 to R.H.S. to obtain the value of y} y=9-5 {as 5 is positive it will become negative when shifted to R.H.S.} y=4 therefore the value of y is 4. CHECK! 5+4=9 9=9
I feel like I'm doing someone's homework! y/9 + 5 = 0 rearranging: y/9 = -5 y = -5 x 9 y = -45
y+9=14 subtract 9 from each side to get y by itself y=5
-2-5
9y + 5 = 0 (-5 on both sides)9y = -5 (/9 on both sides)y = -5/9
You zero out the variables in turn. Y = 9(0) + 5 Y = 5 ---------- 9X + 5 = 0 9X = - 5 X = - 5/9 Can use these points to graph line. ( - 5/9, 5)