How do you write 4x plus 4y equals 40 or how do you solve it? You would write it 4x+4y=40 you would solve it for y by subtracting 4x from both sides 4y=40-4x then divide all of that by 4y=40-4x/4 that's if you were graphing i have no idea what you're asking hope that helps if it's not too late.
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
3x-4x=12 that means -x equals 12 so x equals -12
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
(4, -2)
How do you write 4x plus 4y equals 40 or how do you solve it? You would write it 4x+4y=40 you would solve it for y by subtracting 4x from both sides 4y=40-4x then divide all of that by 4y=40-4x/4 that's if you were graphing i have no idea what you're asking hope that helps if it's not too late.
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
3x-4y=40 (x=0) 3(0)-4y=40 -4y=40 y=40/-4 y=-10 x1 , y1 (13 , -10) (4y=0) 3x-4(0)=40 3x=40 x=40/3 x=13.33 or 13
3x-4x=12 that means -x equals 12 so x equals -12
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
That depends what the value of y is.