if the digits are A and B, then we are given:A + B = 6A * B = (10A + B) / 3∴ B = 6 - A∴ A * (6 - A) = (10A + [6 - A]) / 3∴ 6A - A2 = (9A + 6) / 3∴ 6A - A2 = 3A + 2∴ 6A - A2 - 3A - 2 = 0∴ A2 - 3A + 2 = 0∴(A - 2)(A - 1) = 0∴A ∈ {1, 2}A + B = 6∴ B ∈ {5, 4}∴ The numbers 15 or 24 both meet these conditions.
If the length and width are L and B feet, then 2(L + B) = 36 => L + B = 18 => L = 18 - B L*B = 72 => (18 - B)B = 72 B2 - 18B + 72 = 0 => (B - 6)(B -12) = 0 => B = 6 or B = 12 B = 6 => L = 12 and B = 12 => L = 6 So the dimensions are 6 ft x 12 ft. The dimensions are: length 12 feet and width 6 feet. --- Area = length x width a x b = 72 Perimeter = 2 x length + 2 x width 2a+2b=36 The two equations can be solved by substituting a for b (a2-18a+72=0), with the results a = 6 or 12 and b is the other
-1 2 2 0 x = -1 -4 1 -6 Answer: a = 0 and b = -6
x^2-5x-6+0 (X-6)(x+1) = 0 X = 6 X = -1 or you can use quadratic formula x = (-b+/-sqrt(b^2-4ac))/2 where a = 1 b = -5 c = -6 X = 6,-1
3x2 + bx - 5 = 0 ∴ 3x2 + bx = 5 ∴ x2 + bx/3 = 5/3 ∴ x2 + bx/3 + (b/6)2 = 5/3 + (b/6)2 ∴ (x + b/6)2 = (45 + b2) / 36 ∴ x + b/6 = ±[(45 + b2) / 36]1/2 ∴ x = [-b ± (45 + b2)1/2] / 6
m=4/1 replace x and y with 0 and 6 to get 6=4(0)+b then we can deduce that b=6 so the equation would be y=4x+6, or 4x-y+6=0
6 (or 0)
if the digits are A and B, then we are given:A + B = 6A * B = (10A + B) / 3∴ B = 6 - A∴ A * (6 - A) = (10A + [6 - A]) / 3∴ 6A - A2 = (9A + 6) / 3∴ 6A - A2 = 3A + 2∴ 6A - A2 - 3A - 2 = 0∴ A2 - 3A + 2 = 0∴(A - 2)(A - 1) = 0∴A ∈ {1, 2}A + B = 6∴ B ∈ {5, 4}∴ The numbers 15 or 24 both meet these conditions.
Here is a daily update of who are definitely through to the Round of 16 and who are eliminated for World Cup 2014. In brackets are Group & Points to date.After 21 June matches:5 Teams in: Netherlands (B,6), Chile (B,6), Colombia (C,6), Costa Rica (D,6), Argentina (F,6)5 Teams out: Cameroon (A,0), Australia (B,0), Spain (B,0), England (D,0), Bosnia & Herzegovina (F,0)So 27 teams are playing for the remaining 11 spots.
-6 is rational, as it can be written as 1/b (-6/1). An example of an irrational number is pi, as it has an infinite amount of decimal places.
16
xor swap is the swap you are asking for XORSwap( int a, int b ) { a = a ^ b; b = a ^ b; a = a ^ b; } xor is a bitwise operation like '&'(and) and '|'(or) but with the resulting value being one but not the other. 0 ^ 0 is 0 1 ^ 0 is 1 0 ^ 1 is 1 1 ^ 1 is 0 so if a is 6 and b is 3 a is 110 in binary b is 011 in binary step 1 a = a ^ b; a = 110 ^ 011 1 ^ 0 = 1 1 ^ 1 = 0 0 ^ 1 = 1 a is 101 after step 1 b remains 011 after step 1 step 2 b = a ^ b; b = 101 ^ 011 1 ^ 0 = 1 0 ^ 1 = 1 1 ^ 1 = 0 a remains 101 after step 2 b is 110 after step 2 step 3 a = a ^ b; a = 101 ^ 110 1 ^ 1 = 0 0 ^ 1 = 1 1 ^ 0 = 1 a is 011 after step 3 b remains 110 after step 3 a started as 110 ( 6 ) b started as 011 ( 3 ) a ended as 011 ( 3 ) b ended as 110 ( 6 ) no extra variables needed
If the length and width are L and B feet, then 2(L + B) = 36 => L + B = 18 => L = 18 - B L*B = 72 => (18 - B)B = 72 B2 - 18B + 72 = 0 => (B - 6)(B -12) = 0 => B = 6 or B = 12 B = 6 => L = 12 and B = 12 => L = 6 So the dimensions are 6 ft x 12 ft. The dimensions are: length 12 feet and width 6 feet. --- Area = length x width a x b = 72 Perimeter = 2 x length + 2 x width 2a+2b=36 The two equations can be solved by substituting a for b (a2-18a+72=0), with the results a = 6 or 12 and b is the other
-1 2 2 0 x = -1 -4 1 -6 Answer: a = 0 and b = -6
Six Balls to an Over in Cricket.
x^2-5x-6+0 (X-6)(x+1) = 0 X = 6 X = -1 or you can use quadratic formula x = (-b+/-sqrt(b^2-4ac))/2 where a = 1 b = -5 c = -6 X = 6,-1
3x2 + bx - 5 = 0 ∴ 3x2 + bx = 5 ∴ x2 + bx/3 = 5/3 ∴ x2 + bx/3 + (b/6)2 = 5/3 + (b/6)2 ∴ (x + b/6)2 = (45 + b2) / 36 ∴ x + b/6 = ±[(45 + b2) / 36]1/2 ∴ x = [-b ± (45 + b2)1/2] / 6