m=4/1 replace x and y with 0 and 6 to get 6=4(0)+b then we can deduce that b=6 so the equation would be y=4x+6, or 4x-y+6=0
y=-3x-2
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
-12
4
y = mx + b where m is the slope and b is the y-intercept
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Slope-intercept form
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y=-3x-2
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
It is: y-7 = -3(x--3) => y = -3x-2
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
-12
sda
y= slope + y-intercept