8+b^2=10
b^2=2 Subtracted 8 from both sides
b=2^1/2 Took square root of both sides
6 squared is 36, and 8 squared is 64. Adding these together, 36 + 64 equals 100. Therefore, 6 squared plus 8 squared equals 100.
It is: 3x2+6x-11 = 0
It is a quadratic equation in the variable x.
-10 + 8 = -2
Tautology?
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
104
6 squared is 36, and 8 squared is 64. Adding these together, 36 + 64 equals 100. Therefore, 6 squared plus 8 squared equals 100.
To calculate 6 squared plus 8 squared, you first need to square each number individually. 6 squared is 6 x 6, which equals 36. 8 squared is 8 x 8, which equals 64. Adding these two results together, you get 36 + 64, which equals 100. So, 6 squared plus 8 squared is 100.
4
It is: 3x2+6x-11 = 0
y = x - 4 x^(2) + y^(2) = 8 Hence y^(2) = 8 - x^(2) Square up the linear eq'n and substitute Hence y^(2) = ( x - 4)^(2) NB Notice the RHS is wholly squared , not individual terms. Substitute ; this eliminates 'y' ( x - 4)^(2) = 8 - x^(2) Square out the brackets x^(2) - 8x + 16 = 8 - x^(2) Collect terms 2x^(2) -8x +8 = 0 Factor 2(x^(2) - 4x + 4) = 0 (x- 2)(x - 2) = 0 Hence x = 2 ( The 'x' coordinate) . Substitute into either eq;n for 'y' y = 2 - 4 y = -2 Hence ( x,y) = ( 2,-2) ; The point of contact of the tangent and the curve.
It is a quadratic equation in the variable x.
-10 + 8 = -2
Tautology?
* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4