it's called a composite number [ a number greater than 1 w/ more than two factors.]
2w + 2
3w + 5
w2+2w=99w2+2w-99=0 (quadratic equation)Find two number that multiply to get 99 and add to get 2The numbers are 11 and -9soooo.(w-9) (w+11)=0w-9=0 w+11=0w= 9 w=-11
It is W - 1. If the remainder is greater than or equal to W, then you can subtract W from the remainder and increase the quotient by 1.
w=3,z=9. z2+4(w+5)=
Designate w as the number of games won. The total of 25 must be the sum of the number of games won, the number lost, and the number tied. From the statement of the problem, the number of games lost must be 9 more than the number of games lost, or w + (w-9) equals number of games played minus number of games tied, or 2w - 9 = 25 - 2; 2w = 23 + 9 = 32; w = 16.
45
it's called a composite number [ a number greater than 1 w/ more than two factors.]
2w + 2
The answer will depend on what W is. Unfortunately, you have not bothered to share that information and so the question cannot be answered.
(3w(3w)/3w) + 5
3w + 5
Call the number I am thinking of W ( for WikiAnswers) 2W+12=30 So 2W=18 W is 9 The number is 9
w + 5
The number W
Six less than a number w squared is written algebraically as w2 - 6