3b -2 =7 b+4
-7+3b = 4b-8 3b-4b = -8+7 -b = -1 b = 1
If: 7+3b = 61 Then: b = 18
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
Write down both equations (I'll label them (1) and (2)):(1) a = 3b - 4(2) a + b = 16Pass b to the left side of the equation (1):(1) a - 3b = -4(2) a + b = 16Multiply (1) by -1:(1) -a + 3b = 4(2) a + b = 16Add down both equations:-a + 3b + a + b = 4 + 164b = 20b = 5Replace b in (2):a + 5 = 16a = 11
3b -2 =7 b+4
In the inequality 3b 7 32 b<13.
-7+3b = 4b-8 3b-4b = -8+7 -b = -1 b = 1
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3
If: 7+3b = 61 Then: b = 18
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
Write down both equations (I'll label them (1) and (2)):(1) a = 3b - 4(2) a + b = 16Pass b to the left side of the equation (1):(1) a - 3b = -4(2) a + b = 16Multiply (1) by -1:(1) -a + 3b = 4(2) a + b = 16Add down both equations:-a + 3b + a + b = 4 + 164b = 20b = 5Replace b in (2):a + 5 = 16a = 11
A plus b 4 can be assumed that mathematically, a = +4.
Set up the equation: 3b-2=7. Solve for b: Subtract 2 from both sides: 3b=9. b=3.
26 = 3b - 2 - 7b 28 = -4b b = -7
b= 4