To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
To determine the percentage of As-81 that remains undecayed after 43.2 seconds, you would need to know its half-life. As-81 has a half-life of approximately 46.2 seconds. Using the formula for radioactive decay, after one half-life (46.2 seconds), 50% would remain. Since 43.2 seconds is slightly less than one half-life, a little more than 50% of the sample remains undecayed, but the exact percentage requires calculations based on the exponential decay formula.
To determine the percent of As-81 that remains un-decayed after 43.3 seconds, you would need to know its half-life. The half-life of As-81 is approximately 46.2 seconds. Given that 43.3 seconds is slightly less than one half-life, you can use the formula for exponential decay: [ N(t) = N_0 \left( \frac{1}{2} \right)^{t/T_{1/2}} ] where ( N_0 ) is the initial quantity, ( t ) is the elapsed time, and ( T_{1/2} ) is the half-life. After 43.3 seconds, about 80% of the original sample of As-81 would remain un-decayed.
The half-life of Cu-61 is approximately 3 hours, meaning that after each half-life, half of the remaining sample decays. After 9 hours, which is three half-lives (3 hours x 3 = 9 hours), the original 2 mg sample would have gone through three decay cycles. Thus, the amount remaining would be (2 , \text{mg} \times \left(\frac{1}{2}\right)^3 = 2 , \text{mg} \times \frac{1}{8} = 0.25 , \text{mg}).
There are 60 seconds in a minute. Two minutes would be 120 seconds. This would mean there are 2 minutes and 2 seconds in 122 seconds.
Sample size is the number of samples arawn from a population. If you drew 20 samples, your sample size would be 20.
After 76 seconds, half of the radium-222 would have decayed (its half-life is about 3.8 days). Therefore, the quantity of radium-222 remaining in the 12-gram sample would be 6 grams.
less bias and error occur when sample size is larger
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
To convert 9435 seconds into hours, minutes, and seconds, you would first divide 9435 by 3600 (the number of seconds in an hour) to get 2 hours. Next, you would take the remaining seconds (2355) and divide by 60 (the number of seconds in a minute) to get 39 minutes. Finally, the remaining seconds would be 15 seconds. Therefore, 9435 seconds is equivalent to 2 hours, 39 minutes, and 15 seconds.
Based on the half-life of Na-24, after 1 half-life (15 hours), there would be 500 atoms remaining. After 2 half-lives (30 hours), there would be 250 atoms remaining. After 3 half-lives (45 hours), there would be 125 atoms remaining in the sample.
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
After 1.6 seconds, 0.6 g astatine-218 remains unchanged. This amount is reduced by half to 0.3 g at 3.2 seconds. It is halved again at 4.8 seconds to 0.15 g, and halved once more to 0.075 g unchanged after a total of 6.4 seconds.
To find the mass of K-42 remaining after 37.2 hours, we would need additional information such as the half-life of K-42. Without this information, it is not possible to calculate the remaining mass.
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
To determine the percentage of As-81 that remains undecayed after 43.2 seconds, you would need to know its half-life. As-81 has a half-life of approximately 46.2 seconds. Using the formula for radioactive decay, after one half-life (46.2 seconds), 50% would remain. Since 43.2 seconds is slightly less than one half-life, a little more than 50% of the sample remains undecayed, but the exact percentage requires calculations based on the exponential decay formula.
There could be a few different reasons on why a dentist would recommend a partial versus and having teeth pulled. The main reason would probably be because the teeth are no more good.
To determine how much of a 100 gram sample would remain unchanged after 2 hours, it is necessary to know the specific decay rate or change process of the sample. For example, if the sample undergoes a decay process with a known half-life, you can calculate the remaining amount using the formula for exponential decay. Without this information, it's impossible to provide an exact answer. In general, if no decay occurs, the entire 100 grams would remain unchanged.