To determine the percentage of As-81 that remains undecayed after 43.2 seconds, you would need to know its half-life. As-81 has a half-life of approximately 46.2 seconds. Using the formula for radioactive decay, after one half-life (46.2 seconds), 50% would remain. Since 43.2 seconds is slightly less than one half-life, a little more than 50% of the sample remains undecayed, but the exact percentage requires calculations based on the exponential decay formula.
The answer depends on 3240 WHAT: seconds, days, years?
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Sample X is likely a solution containing a soluble substance (B) and an insoluble substance (Y). When passed through the filter paper, the insoluble substance Y is caught while the soluble substance dissolves in liquid Z, which passes through. Upon vaporizing liquid Z, the soluble substance B remains as a white residue. Thus, sample X is a mixture of an insoluble solid (Y) and a soluble compound (B).
As the sample size increases, the standard deviation of the sample mean, also known as the standard error, tends to decrease. This is because larger samples provide more accurate estimates of the population mean, leading to less variability in sample means. However, the standard deviation of the population itself remains unchanged regardless of sample size. Ultimately, a larger sample size results in more reliable statistical inferences.
try using my formula.... ar=a(1/2)^2t therefore, 57(.05) = 57(1/2)^2t and 57s cancels out, .05 = 1/2^2t log .05 = log .5^2t divide log .5 from both sides, 4.32 = 2t t = 2.16, therefore 126 seconds or 2 minutes and 6 seconds
1.5% remains after 43.2 seconds.
After 50 years, approximately 50% of tritium will remain undecayed in a sample. Tritium has a half-life of about 12.3 years, which means that the amount of undecayed tritium decreases by half every 12.3 years.
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75
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
By definition, 50%. Half life is the time for half of the original sample to decay.
An eighth remains.
It tells what fraction of a radioactive sample remains after a certain length of time.
To find the percent composition of NaHCO3 in a sample, you would calculate the mass of NaHCO3 in the sample divided by the total mass of the sample, then multiply by 100 to get the percentage.
In reality, as the atoms gets decayed it gives out radiations such as alpha, beta and Gama. Alpha is a helium nucleus which is massive and beta is electron but fast moving and Gama is an electromagnetic radiation. So as the atom decays then its mass is likely to be reduced. Rutherford's radioactive law deals with the number of atoms undecayed present at an instant 't' given in the form N = No e-lambda t Here No is the total atoms present both decayed and undecayed in a sample. N is the number undecayed present lambda - the decay constant t - the time elapsed
To find the percent by mass of a compound in a given sample, you need to divide the mass of the compound by the total mass of the sample and then multiply by 100. This will give you the percentage of the compound in the sample.
1/8 of the original amount remains.