The answer depends on 3240 WHAT: seconds, days, years?
because
try using my formula.... ar=a(1/2)^2t therefore, 57(.05) = 57(1/2)^2t and 57s cancels out, .05 = 1/2^2t log .05 = log .5^2t divide log .5 from both sides, 4.32 = 2t t = 2.16, therefore 126 seconds or 2 minutes and 6 seconds
parameter !
No, the size of a radioactive sample does not affect its half-life. The half-life is a characteristic property of a radioactive isotope, defined as the time it takes for half of the radioactive atoms in a sample to decay. This property is intrinsic to the isotope itself and remains constant regardless of the amount of material present. Thus, whether you have a small or large sample, the half-life will remain the same.
1.5% remains after 43.2 seconds.
After 50 years, approximately 50% of tritium will remain undecayed in a sample. Tritium has a half-life of about 12.3 years, which means that the amount of undecayed tritium decreases by half every 12.3 years.
2
75
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
After one half-life, 50% (or half) of the original uranium remains.
An eighth remains.
It tells what fraction of a radioactive sample remains after a certain length of time.
To find the percent composition of NaHCO3 in a sample, you would calculate the mass of NaHCO3 in the sample divided by the total mass of the sample, then multiply by 100 to get the percentage.
The mass of a radioactive isotope remains constant as it decays. However, the atomic nucleus can change due to the emissions of particles or energy, which can result in the isotope transforming into a different element.
To find the percent by mass of a compound in a given sample, you need to divide the mass of the compound by the total mass of the sample and then multiply by 100. This will give you the percentage of the compound in the sample.
1/8 of the original amount remains.