6.7
4.702 m (rounded)
Use pythagorean theorem to solve:
(distance from the wall)2 + (height up the wall)2 = (length of the ladder)2
(height up the wall) = sqrt[ (length of the ladder)2 - (distance from the wall)2 ]
Height = sqrt[ (5)2 - (1.7)2 ]
4
1 i think other people feel free to change this
If h is vertical height, b=horizontal distance from wall to bottom of ladder and l=lenght of ladder,we can say lsquared = hsquared + b squared. Now differentiate w.r.t. time t. 2l*dl/dt= 2h* dh/dt + 2b*db/dt =0 However this solution doesn't give exactly the same answer when one solves the problem geometrically or using simple pythagorus. For example ,if l=20m and b=12 m and h=16m and db/dt is 2m/s, I calculate dh/dt as !.5 m/s using calculus but 1.717 m/s using geometry or straight Pythagorus. Where is the fallasy inthe method using calculus? Ray Bevan
lenght times height == If it rests on one of the shortest sides , then the altitude is the length of the longer side. If it rest on one of the longer sides, then the altitude is the length of the shortest side. If it is the special case of a square, then any side is an altitude.
Foot rests can be bought in a variety of places. One can buy them at furniture stores, home improvement stores, and home supply stores. One may also find foot rests through online retailers.
4
15*cos(60) = 7.5 7.5 m
If the wall is straight and the ground level then this is an outline of a right angle-triangle. If the top of the ladder makes an angle of 530 with the wall then the bottom of the ladder must make 370 to the ground. Use the sine ratio to find the length of the ladder (which will be the hypotenuse) sin = opp/hyp rearranged to hyp = opp/sin hyp = 15/sin370 = 24.92460212 feet So the length of the ladder is 25 feet correct to the nearest foot.
1 i think other people feel free to change this
13 feet
62+82=36+64=100 and the squared route of 100 is 10
this is what i have: my question: ladder: weight = 200N = Mg; length = 10m = L firefighter: weight = 600N = mg He goes up ladder x distance. coefficient is 0.5 50 deg angle between ladder and floor what is the max value of x? -------------------- Ff -Fn Ff = Fn 1) Gn = Mg + mg Gn = 200+600=800 2) Ff = mu*Gn Ff = 0.5 * 800 = 400 3) x = (Ff*L*sin50 - Mg(L/2)sin40) / (mg*sin40) [40 deg is 90-50; the 90 is perpendicular to the ladder] x=[(400*10*sin50)-(200*5*sin40)] / [600*sin40] x = 6.28m for more info see: tycho.physics.wisc.edu/courses/phys201/spring08/Lectures/Solids.pdf
It could mean that they really like you.
In music by any composer rests indicate the length of silence desired.
That's kind of subjective it depends on how old you are, your weight, how tall you are and other factors. So yes you can but it's more risky.
If h is vertical height, b=horizontal distance from wall to bottom of ladder and l=lenght of ladder,we can say lsquared = hsquared + b squared. Now differentiate w.r.t. time t. 2l*dl/dt= 2h* dh/dt + 2b*db/dt =0 However this solution doesn't give exactly the same answer when one solves the problem geometrically or using simple pythagorus. For example ,if l=20m and b=12 m and h=16m and db/dt is 2m/s, I calculate dh/dt as !.5 m/s using calculus but 1.717 m/s using geometry or straight Pythagorus. Where is the fallasy inthe method using calculus? Ray Bevan
On a microscope, the distance from the shoulder on which the eyepiece rests to the shoulder where the screw-in objective is located (nominally 160 mm).