Q: A Gaussian surface does not enclose a charge Does it mean that E equals 0 on its surface?

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The question does not specify what z is so this answer could be completely wrong. However, if the question is in the context of the standard Gaussian distribution, the answer is 0.493613 (to 6 dp)

0.5m-1

Perhaps if you read the question properly, you would not have to ask the question!

That's a Gaussian distribution.

Surface area of a sphere: A = 4πr2So, surface area = 4pi52

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The question does not specify what z is so this answer could be completely wrong. However, if the question is in the context of the standard Gaussian distribution, the answer is 0.493613 (to 6 dp)

divide 0.108 gm by 1 coulomb of charge because e.c.e equals mass in gm/charge

Surface area equals 864cm2

127.5

0.5m-1

Perhaps if you read the question properly, you would not have to ask the question!

No.

0.6 m-1 is the ratio of surface area to volume for a sphere.

That's a Gaussian distribution.

zero .. such an atom is neutral. No net charge

0.4 m-1 is the ration of surface area 588m2 to volume 1372m3 for a sphere.

The answer depends on what measure - volume, surface area - equals 375.