Wiki User
∙ 14y agoa. 144 feet
b. 96 ft/sec.
Wiki User
∙ 14y ago19.6 meters / 64.4 ft
It's not possible to calculate the answer with the information given.An object with a mass of 15 kg can be dropped from a building of any height.
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
They should reach the ground together, since their initial vertical speed is the same, namely zero.
381 metres
Assuming the object is dropped from rest and neglecting air resistance, it would take approximately 7.0 seconds for the object to hit the ground from a height of 500 feet. This is based on the formula t = sqrt(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity (approximately 32.2 ft/s^2).
The height of the building at the 102nd floor is 381 metres. The penny is irrelevant.
The height of the building at the 102nd floor is 381 metres. The penny is irrelevant.
19.6 meters / 64.4 ft
.. You need the height of the building to figure it out..?
A pebble is dropped from the top of a 144-foot building. The height of the pebble h after t seconds is given by the equation h=−16t2+144 . How long after the pebble is dropped will it hit the ground?Interpretationa) Which variable represents the height of the pebble, and in what units?b) Which variable represents the time in the air, and in what units?c) What equation relates the height of the object to its time in the air?d) What type of equation is this?e) What are you asked to determine?
The time it takes for a ball to hit the ground when dropped from a height can be calculated using the equation: t = √(2h/g), where h is the height (443 meters) and g is the acceleration due to gravity (9.81 m/s²). Solving for t gives a time of approximately 9 seconds.
It's not possible to calculate the answer with the information given.An object with a mass of 15 kg can be dropped from a building of any height.
The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height of the building, g is acceleration due to gravity (approximately 9.81 m/s^2), and t is the time taken for the ball to reach the ground (3 seconds in this case). Plugging in the values, we get h = (1/2) * 9.81 * 3^2 = 44.145 meters. Thus, the building is approximately 44.145 meters tall.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
If we assume the time it takes for the ball to stop is directly proportional to the height it is dropped from, we can set up a proportion based on the given information. From the given data, we have the ratio of time to height as 11/1 = 25/2. Therefore, if we continue this ratio, the time it would take to stop if dropped from 3 feet would be 55 seconds.