sin(60) =.866
20m/s*.866 = 17.32m/s in the vertical direction.
x=17.32t - 9.81t2
x=0 when the ball returns to its original height, so 17.32t = 9.81t2
17.32=9.81t
t=1.766sec for the ball to return to its original height. 1/2 this time will be its maximum height.
T=.883 sec.
maximum height = 17.32t - 9.81t2 = 14.4109 - 6.807 = 7.6039 m
420 feet at about an angle of -3 degrees.
An angle above 90 but less than 180 degrees is an obtuse angle An angle above 180 degrees is a reflex angle
20 degrees is a measure of angular displacement. This cannot be converted to lateral (horizontal) displacement.
At 45 degrees. Yay! I got a proof done, check the link below, back to studying derivations for a infinite line of charge, ewww. The Related Question may answer yours. (See below left.)
To determine the angle at which the rock was thrown, we can use projectile motion principles. The vertical height of the building (100 ft) will dictate the time it takes for the rock to fall, while the horizontal distance (160 ft) gives us the horizontal velocity. By solving the equations of motion for both vertical and horizontal components, we can calculate the initial velocity and angle of launch. However, without additional information such as the initial speed, we cannot find a unique solution for the angle.
The velocity is greatest at two points:1). when it leaves the hand of the tosser2). when it returns to the same height as it was when it was releasedThis answer is the same for any angle above horizontal, regardless of the angle.
420 feet at about an angle of -3 degrees.
A trajectory of 45 degrees elevation gives the longest horizontal travel- (not taking air drag into consideration nor any aerodynamic properties of a projectile.
The javelin is ideally thrown at a 45-degree angle to maximize its horizontal distance. This angle allows for an optimal balance between vertical lift and horizontal distance, utilizing the forces of gravity and aerodynamic lift effectively. While the actual optimal angle can vary based on factors like speed and technique, 45 degrees serves as a theoretical benchmark for achieving maximum range in projectile motion.
An angle above 90 but less than 180 degrees is an obtuse angle An angle above 180 degrees is a reflex angle
Fifteen degrees from the horizontal.
No, this is an example of projectile motion. You should throw it at 45 degrees from the horizontal ground for it to have the maximum horizontal distance. This is because a sufficient height must be achieved, so that the ball can stay in the air longer and thus travel a longer distance while in flight.
An obtuse angle is an angle between 90 degrees and 180 degrees. A 180 degree angle is a straight horizontal line. So you can imagine that a 160 degree angle is almost but not quite horizontal.
65
It is a line that is not at an angle of 90 degrees to the horizontal!
Smaller angles will result in a larger horizontal velocity and smaller vertical velocity. The times of flight will also be shorter since it's closer to the ground. Larger angles have a larger vertical velocity and smaller horizontal velocity. Time of flight will be much longer since it is higher above the ground. As for distance, 45 degrees will result in the greatest distance and for every distance before the furthest one there is an angle above 45 degrees and an angle below 45 degrees that will result in that distance.
20 degrees is a measure of angular displacement. This cannot be converted to lateral (horizontal) displacement.