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A ball is thrown with a velocity of 40 meters per second at an angle above the horizontal. If the ball attains its maximum range what was the value of the angle?
Queee
At 45 degrees.
Yay! I got a proof done, check the link below, back to studying derivations for a infinite line of charge, ewww.
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If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
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When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?
'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters
An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
If a slide went vertical for 100 meters then horizontal for 10 and vertical again for another 90 meters would you survive or be flung off at the 10 meter horizontal?
Yes.
Which is the total velocity of a projectile at maximum height?
At the maximum height of projectile motion, the vertical component of velocity is zero while the horizontal component of velocity remains constant. Therefore, the total velocity of the projectile at the maximum height is equal to the magnitude of its horizontal component of velocity.
What is the maximum allowable length of a horizontal cable?
There are two different ways of looking at this. The maximum length from end to end from the telecommunications closet to the wor karea device is 100 meters. The horizontal cable itself is usually a maximum of 90 meters, with 10 meters maximum from the wall plate to the device in the work area.
The maximum velocity of a ball as it drops is 12 meters per second. The maximum velocity of the ball after the first bounce is -6 meters per second. What is the difference between the two velocities?
18
What is acceleration at instantaneous maximum velocity?
The acceleration at instantaneous maximum velocity is zero, as the velocity is not changing at that moment.
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
A shell is fired from the ground with an initial velocity of 1600m s at an angle of 64 to the horizontal What is the shells horizontal range?
Using the projectile motion equations and given the initial velocity and angle, we can calculate the time the shell is in the air. Then, we can find the horizontal range by multiplying the time of flight by the horizontal component of the initial velocity. The horizontal range in this case is about 1056 meters.
What is the maximum distance for a run of horizontal cabling that extends from a repeater to any workstation?
90 meters
What is the maximum distance specified in the structured cabling standard for a horizontal wiring system?
90 Meters+ 10 meters for running cables so 100 meters is the total.
What is the average acceleration of car if it travels in a straight line in one minute and it attains a velocity of 40 meters second second and it finally?
There is not enough information to answer the question. The initial velocity of the car is not given. Also, the "it finally" at the end of the question does not make sense.
Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0 and Acirc and deg. If the ball moves through the air for 3.2 seconds what is the horizontal distance tr?
To find the horizontal distance traveled by the soccer ball, you can use the equation: horizontal distance = horizontal velocity x time. The horizontal velocity is given by the formula Vx = V0 cosθ, where V0 is the initial velocity and θ is the angle of projection. Substituting the given values: Vx = 10.0 m/s * cos(30°) = 8.66 m/s. Then, the horizontal distance = 8.66 m/s * 3.2 s = 27.71 meters.
A ball is thrown horizontally from a cliff at a speed of 8 meters per second. What is its speed one second later?
After a second, the ball will still have a horizontal velocity of 8 meters per second. It will also have a vertical velocity of 9.8 meters per second (Earth's acceleration is about 9.8 meters per square second). The combined speed (using the Law of Pythagoras) is about 12.65 meters per second.
If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
