0
What is the probability that a colorblind woman and a man with normal vision will have a colorblind daughter?
Wiki User
∙ 10y ago
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What is the probability that a woman who is a carrier of the colorblind gene and a color blind man will have a first son who will be color blind?
The probability is 0 (but the daughter will be a carrier of the color blind gene). This is because the gene dictating whether someone is color blind or not is linked to the X chromosome (and not the Y). The color blind gene is a recessive gene whilst the normal color vision gene is a dominant gene. Hence if a girl (XX) has one normal vision gene (from one parent) and one color blind gene (from the other parent), her normal vision gene will be dominant to the recessive color blind gene and hence she will have normal vision (but she will be a carrier of the color blind gene). If both her parents contribute the recessive color blind gene to her, then she will be color blind. For a woman (XX) to be color blind, she needs to be have both genes to be recessive (ie where there is no dominant normal color vision gene to dominate). For a man (XY), as long as the X gene contributed by his mother is a color blind gene, he will be color blind because he has no other X chromosome where a dominant normal color gene could reside. Hence, to answer the question, a man with normal color vision (XY, with a dominant normal color vision X gene since the gene can't be the recessive color blind gene otherwise he will be colorblind) and a colorblind woman (XX, both recessive color blind genes), will each contribute an X each the child. The man will contribute his only X chromosome which carries the normal color vision X gene and the woman can only contribute a recessive color blind gene. The man's normal color vision X gene will be dominant, and hence the daughter will definitely have normal vision (despite being a carrier).
What is the probability that a woman whose father was color blind will have a son who is color blind?
50%. 1 of the two male offspring will definately be color blind. Do a punnett square with the father having normal vision and the mother being a carrier.
What is the vision statement of six sigma?
The vision of Six Sigma is to delight customers by delivering world-class products and services through achieving the highest levels of performance in everything you do
Which degree is better between applied mathematics computer science and statistics and which one is the second one?
It's not that one is better than the other, it's just that they are different. The question is, "which one is better for you?" The first thing you must do is acquire a vision for yourself; a specific and clearly articulated picture of the future you intend to create for yourself. This vision should be based on a passion for what you want to do, and the benefit it brings to others as well as yourself. Once you acquire that vision your path will become clear. Each of these fields have possibilities, but only passion will lead to success. Passion is key to success.
How do you use synoptophore?
It is a piece of equipment used by orthoptists who specialize in dealing with eye squints and binocular single vision. The synoptophore can help to measure the angle of the squint present i.e how big it is and you can measure the angle in different position of gazes. it cam also be use to measure vertical and torsional deviations. Motor and sensory fusion can also be measure along with stereopsis (3D) vision . First the patient's IPD is set by keeping your head straight and aligning the patient's eyes with the white line on the eyepieces. To measure the angle of deviation the tubes are moved in towards you if it is an inward deviation and move the tube away from you to measure a outward deviation in degrees. For sensory and motor fusion the tubes are converged and then diverged until the patient cant see the image as single .
What is the probability that a colorblind women and a man with normal vision will have a colorblind son?
50%Answer100%
What is the probability that a colorblind female and a normal color vision male will produce an colorblind offspring?
100% of all male offspring will be colorblind. 0% of all femal offspring will be colorblind.
A male who has normal vision marries a female who is a carrier for colorblindness can they have a colorblind daughter?
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
A women wo isn't colorblind but has an allele for color blindness reproduces with a man who has normal vision what is the chance that they'll have a colorblind daughter?
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
A colorblind man and woman with normal vision whose father was colorblind have a son what is the probability that their son is colorblind?
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
If Couples that have normal vision what is the probability of them having a color blind daughter and color blind son?
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
A mother has one allele for color blindness and one allele for nomal vision what is the probability that her gamete will have the allele for color blindness?
Color Blindness is x-linked recessive. Therefore, it could not be heterozygous; the daughter would not be colorblind, but rather have normal vision.
Can two persons with normal vision produce a colorblind son?
No they will produce a child who is colour blind.
What is the probability that a woman who is a carrier of the colorblind gene and a color blind man will have a first son who will be color blind?
The probability is 0 (but the daughter will be a carrier of the color blind gene). This is because the gene dictating whether someone is color blind or not is linked to the X chromosome (and not the Y). The color blind gene is a recessive gene whilst the normal color vision gene is a dominant gene. Hence if a girl (XX) has one normal vision gene (from one parent) and one color blind gene (from the other parent), her normal vision gene will be dominant to the recessive color blind gene and hence she will have normal vision (but she will be a carrier of the color blind gene). If both her parents contribute the recessive color blind gene to her, then she will be color blind. For a woman (XX) to be color blind, she needs to be have both genes to be recessive (ie where there is no dominant normal color vision gene to dominate). For a man (XY), as long as the X gene contributed by his mother is a color blind gene, he will be color blind because he has no other X chromosome where a dominant normal color gene could reside. Hence, to answer the question, a man with normal color vision (XY, with a dominant normal color vision X gene since the gene can't be the recessive color blind gene otherwise he will be colorblind) and a colorblind woman (XX, both recessive color blind genes), will each contribute an X each the child. The man will contribute his only X chromosome which carries the normal color vision X gene and the woman can only contribute a recessive color blind gene. The man's normal color vision X gene will be dominant, and hence the daughter will definitely have normal vision (despite being a carrier).
What is the vision of dogs?
doggies=colorblind
What percentages can be expected in the offspring of cross between a female carrier for color blindness and a male with normal color vision?
50% probability that the sons produced from this union will be color blind. 50% probability that a son will not have the disease. 50% probability that a daughter will be a carrier of the allele for color blindness. 50% probability that a daughter will not be a carrier. Phenotypically this would be 1male color blind, 1 male not color blind, 1 female carrier and 1 female non-carrier. Assuming that the probability of male and female offspring is identical...this would be 25% of each genotype mentioned above. Based on phenotype, without regard to sex the percentages of normal to colorblind would be 75% to 25% with the 25% displaying the characteristic all being male.
A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
