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Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.

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In humans normal color vision is dominant over colorblindness. A colorblind male marries a female who is a carrier for color blindness. What is the probability that a colorblind child would be born to?

The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.


If a color blind male who has normal clotting blood marries a female who is a carrier of hemophilia and has normal color vision could they have a color blind child?

In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.


A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?

Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.


If a color blind woman marries a man with normal vision the children will be?

there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.


If a normal woman whose father is color-blind marries a colorblind man what are their chances of having a colorblind son?

50%


Why is colorblindness more common in males?

It's because it's, what we call, a "sex-linked disorder." You see, men have "xy" chromosomes, and women have "xx" chromosomes. In a sex-linked disorder, all "x" chromosomes in either of the genes have to be affected. if you see an affected x chromosome, it would look something like this "xa". The "y" chromosomes don't become affected, I don't think. Women who have only one x chromosome affected are called "carriers," meaning they aren't affected by the disorder, but they carry it in their genes and can pass it on to their offspring. They don't ALWAYS pass on to the child, but it CAN happen. So why is it easier for men to become colorblind? They have less x chromosomes. If you need more help understanding how that works, google "Colorblindness and punnet square." The Punnet Square is very important to add to your research! if you're curious.


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no she marries edward Jacob falls in love with rennesme-Bella and Edwards daughter no she marries edward Jacob falls in love with rennesme-Bella and Edwards daughter


1. Noah has hemophilia and he marries Patricia who is a carrier for hemophilia. What is the probability that their children will have the disease?

50


1 Noah has hemophilia and he marries Patricia who is a carrier for hemophilia. What is the probability that their children will have the disease?

50


What are the offsprings when woman who is a carrier for colorblindness marries a man who has colorblindness?

The most common type of color blindness is a sex-linked trait, meaning the gene is carried on the chromosomes that determine sex. In this case, it's carried on the X chromosome. There are other types of color blindness that are inherited that are not sex-linked, so it doesn't matter which parent is the carrier. Males are XY, and therefore can pass either an X or Y to their offspring, making them the actual determinants of the sex of the offspring. Females are XX, and so can only contribute an X. In the case of color blindness, since males only get one X, if that has the gene for color blindness on it, the male will be color blind (in this case, we'll call that one "x" rather than "X". In the case of females, she has two - so if only ONE of her X has the gene, she will be a carrier, but will not have it (Xx). If her father is colorblind (xY), and her mother is a carrier (Xx), she has a 50% chance of being colorblind (she'll either be "xx" or "Xx). If her mother IS colorblind (xx) and her father is too (xY), then there is only one outcome: "xx". So, if a color blind mother (xx) has children with a non color blind father (XY), there are the possibilities: xX, xY. Her daughters will be carriers, and her sons will be color blind. If a color blind mother (xx) has children with a color blind father (xY), then these are the possibilities: xx, xY. All children will be color blind. To sum up, a mother with sex-linked colorblindness will always have color blind sons, and daughters will have a 50% chance of being color blind, depending on if the father is or not.


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