4 centimeters cubed!
Density = grams/cm3
Density = 13 g/4 cm3
= 3.25 g/cm3
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The question cannot be answered. Density is a measure of mas per unit volume, or the ratio of mass and volume. 13 millimetres is a measure of distance or length: there is no information in the question about the volume.
1 gm/ml
density = mass / volume = 13 g / 5 cm3 = 2.6 g/cm3
The volume of this cube is 2,197 cm3
13/5 = 2.6 g per cm3
Unit for density is not properly given. Hope it would be 11.4 g per cm3. Then the volume will be got by dividing the given mass by the density. So required volume = mass / density = g /(g/cm3) = 13/11.4 cm3 = 1.14 cm3 nearly
You are supposed to divide the mass by the volume.
Density = Mass/Volume = 12/13 g/ml = 0.923 g/ml approx.
The density of the substance is calculated by dividing the mass (169 grams) by the volume (13 milliliters). Therefore, the density of the substance is 169 grams / 13 milliliters = 13 grams per milliliter.
Use the formula Mass = Density/Volume
Denisty = mass/volume. 13/5 and then convert your units as need be.
To find the volume of the alloy, use the formula for density: Density = Mass / Volume. First, calculate the volume of water displaced by the alloy when immersed: Volume of water displaced = Mass in air - Mass in water. Then, use the density of water (1g/cm^3) to find the volume, as the volume of water displaced equals the volume of the alloy. Finally, calculate the density of the alloy by dividing its mass by the volume obtained.
The question cannot be answered. Density is a measure of mas per unit volume, or the ratio of mass and volume. 13 millimetres is a measure of distance or length: there is no information in the question about the volume.
The rock has a density of 10 g/cm3
depends on his mass and volume...as density=mass/volume.
1 gm/ml
You'll need the density of this stuff ??IT?? which I don't know what stuff it is.Density (g/mL) says how much mass (g) is in a certain volume (mL) of that particular substance.So you have to divide mass, 13g, by the density in g per mL (or kg per L) to find the volume in mL as outcome of that.