0
h=78.4 meters
g=9.8 m/s^2
v=15 m/s
t=falling time
The ball will travel straight ahead at velocity v for time t and also fall down at the same time. The time t is the same time it takes for the ball to reach the ground. Because h=(1/2)*g*t^2 => t=sqrt(2*h/g). The distance traveled is v*t=sqrt(2*h/g)*v=sqrt(2*78.4 m/(9.8 m/s^2))*15 m/s=60 meters.
Answer: The distance traveled is 60 meters.
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