Q: A line contains at least one point?

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no because it has lengthIn complex geometry, an imaginary line is a straight line that only contains one real point.

Infinitely many. Each line segment contains one point which bisects it. Any one of the infinite lines through that point, apart from the original line, is a bisector.

I'd feel a lot more comfortable if you said "... can contain one line and a point ...".When you say "pass through one line", I picture a sword passing through a tight pieceof string. If that's how your plane passes through the line, then the statement in your"question" is false. If your plane contains the line and the extra point, then the statementis true ... only one plane can do that.

The y-intercept identifies one point on a line. You need at least two points to determine a straight line.

that is one point, you need at least two for a line.

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no because it has lengthIn complex geometry, an imaginary line is a straight line that only contains one real point.

In mathematics, an accumulation point is a point such that every neighbourhood of the point contains at least one point in a given set other than the given point.

One point cannot make a line or even a piece of a line. You need at least two points (in projective geometry) and infinitely many in classic geometry.

Infinitely many. Each line segment contains one point which bisects it. Any one of the infinite lines through that point, apart from the original line, is a bisector.

No, a plane can contain only one point of a line. Picture a piece of paper with a pencil stabbed through it. The paper is the plane, and the pencil is the line. The pencil/line only touches the paper/plane at one point. Hope this helped! If it did, please recommend me. -Brad

Every line segment has exactly one bisection point - not "at least one".A line segment has a length that is a finite real number, x, of some measurement units. Every real number can be divided by 2 to give another real number, y. Therefore y = x/2 or x = 2y.A point that is y units from one end of the line will also be x - y = 2y - y = y units from the other end. That is the point is the bisection point.

I'd feel a lot more comfortable if you said "... can contain one line and a point ...".When you say "pass through one line", I picture a sword passing through a tight pieceof string. If that's how your plane passes through the line, then the statement in your"question" is false. If your plane contains the line and the extra point, then the statementis true ... only one plane can do that.

The y-intercept identifies one point on a line. You need at least two points to determine a straight line.

that is one point, you need at least two for a line.

The least needed information can be given in different formats, which are equivalent: -- the slope of the line and its intercept on either axis -- the slope of the line and any one point on it -- any two points on the line

Yes, every isosceles triangle has at least one line of symmetry, usually drawn down the middle from the top point, down in the middle of the triangle's base.

Three or more points are collinear if they are all in the same straight line. They are non collinear if at least one of them is not on the same line as the rest. Four or more points are coplanar if they are all in the same plane. They are non coplanar if at least one of them is not on the same plane as the rest.