There are a lot of them, so I'm sure you don't want us to list them all. If you want 0-9, and are happy with repeat digits, then it's 10*10*10*10 = 10000 combinations. If it's 1-9 and are happy with repeat digits, then it's 9*9*9*9 = 6561 combinations. 0-9 without repeat digits is 10*9*8*7 = 5040 combinations 1-9 without repeat digits is 9*8*7*6= 3024 combinations
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
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If you can't repeat digits and the order of the digits matters,you can make (9 x 8 x 7 x 6) = 3,024 patterns.If you can't repeat digits and the order of the digits doesn't matter,you can make (9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126 unique groups.If you can repeat digits and the order of the digits matters,you can make (9 x 9 x 9 x 9) = 6,561 patterns.If you can repeat digits and the order of the digits doesn't matter,you can make 273 unique groups.
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There are a lot of them, so I'm sure you don't want us to list them all. If you want 0-9, and are happy with repeat digits, then it's 10*10*10*10 = 10000 combinations. If it's 1-9 and are happy with repeat digits, then it's 9*9*9*9 = 6561 combinations. 0-9 without repeat digits is 10*9*8*7 = 5040 combinations 1-9 without repeat digits is 9*8*7*6= 3024 combinations
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
The digits of pi neither repeat or end. They go on forever, but they do not repeat themselves. (Pi is a irrational number, it cannot be written as a fraction).
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
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0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.
The first digit can be one of five integers (1 to 5) The second - fourth digits one of six integers (0 to 5). So: number of (valid) combinations is 5*6*6*6=1080 * * * * * This gives the number of permutations, not combinations. I am working on the latter.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
That depends on . . . -- how many digits you want in each combination -- whether it's allowed to repeat the same digit -- whether the order of the digits in the combination matters, i.e. whether you actually want combinations or permutations. Each choice has a different answer.
Assuming you cannot repeat any of the four digits, possible combinations are... 4789 - 4798 - 4879 - 4897 - 4978 - 4987 7489 - 7498 - 7849 - 7894 - 7948 - 7984 8479 - 8497 - 8749 - 8794 - 8947 - 8974 9478 - 9487 - 9748 - 9784 - 9847 - 9874