0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.
0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.
0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.
0.076923076923076923076923076923076 ... The digits 076923 repeat over and over.
Any two digit number that fits the formula 3n+1 For example if n=4, 3x4+1=13 which fits your question.
To find the units digit of 3 to the 200th power, we need to observe the pattern of units digits as we raise 3 to higher powers. The units digit of 3 to any power follows a repeating cycle: 3, 9, 7, 1. Since the cycle has a length of 4, we can divide 200 by 4 to find the remainder. 200 divided by 4 gives a remainder of 0, meaning the units digit of 3 to the 200th power is the last digit in the cycle, which is 1.
1 divided by 2 = 0.5 1 divided by 13 = 0.07692 (rounded) 13 divided by 2 = 6.5 13 divided by 13 = 1
2506 2506 is divisible by 7. (6 is 3 times of 2; 2+5+0+6=13; 5=6–1)
Its Impossible. I say this because anything that is three digits divided by a one digit number that equals 8 is not possible. For example the higher 1 digit number that you can multiply by eight is nine so I did 8x9 and got 72 which is not a three digit number. The lowest three digit number that 8 goes into is 104 which is 13x8 and 13 is not a one digit number. Therefore the problem is impossible. :)
1 divided by 13 equals 13
1 and 13.
1
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
Impossible. Anything divided by 1 is itself.
13
14.75