20kg
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Another contributor jumped in:
The man's mass doesn't change. He carries 50 kg with him wherever he goes.
But his weight changes, depending on the acceleration of gravity where he is.
Weight = (mass) times (acceleration of gravity).
So we need to find the acceleration of gravity at 2 radii above the surface.
The acceleration of gravity is proportional to the square of the distance from the
place to the center of the earth, and on the surface, it's 9.8 m/s2 .
On the surface, you're 1 radius from the center. At 2 radii from the surface, you're
2 more radii from the center, or 3 radii all together. So your distance from the center
has tripled.
The acceleration of gravity is 1/32 of its original value, or 1/9th of 9.8 .
9.8/9 = 1.089 m/s2 at that position in space.
The man's weight is (mass) times (acceleration of gravity).
On the surface, he weighs (50 x 9.8) = 490 newtons (110.2 pounds).
Out there at 3 radii from the center, he weighs (50 x 1.089) = 54.4 newtons (12.25 pounds).
BSA = 0.007184 x Weight (kg)^0.425 x Height (cm)^0.725
There is no weight ratio for height. The weight of an object depends on its the volume and density. The volume depends on the height as well as the average cross section so height, alone, cannot determine weight.
It is pounds. An inch is the measuring unit for height. A pound is the measuring unit for weight. The logic is as follows. height, weight -> (measuring unit for height), (measuring unit for weight) Some similar examples, If it were "height, distance and inches." the missing word would be "miles" If it were "height, age and inches." the missing word would be "years"
Weight*Height Mass*9.8*Height \
Weight = mg (mass x gravity).
10bls
The weight of any object on the surface of the moon is 16.55% of its weight on the surface of the Earth.
Pressure varies with height as a function of specific weight. p=p0+specific weight*height Where height is the distance below the reference pressure p0 (usually at a free surface).
Pressure varies with height as a function of specific weight. p=p0+specific weight*height Where height is the distance below the reference pressure p0 (usually at a free surface).
Gravitational potential energy.
You need both height and weight to calculate body surface area.
The weight of an object becomes half at a height where the gravitational force is half of the force on Earth, about 3,578 km above Earth's surface. At this height, the object and Earth are attracted with equal and opposite force.
The two variables that determine gravitational potential energy are height above earths surface mass (also air resistance may come into play but in physics friction and air resistance are usually ignored and)
Spacecraft discard their fuel tanks and booster rockets once they have left Earth's surface to reduce weight and improve efficiency. Once the fuel in the tanks is consumed and the booster rockets have propelled the spacecraft into orbit, they are no longer needed and would only add unnecessary weight and drag. By discarding them, the spacecraft can operate more efficiently and maneuver in space more easily.
Isostacy refers to an equilibrium level maintained by the earths crust on top of the mantle. The theory holds that the weight of the earths crust will displace a certain amount of the underlying mantle, and that an equilibrium is reached whereby the mass of the displaced crust and the mass of the displaced mantle are equal, thus holding that part of the crust at a certain height.
The type of potential energy dependent upon an object's weight and distance from Earth's surface is gravitational potential energy. It is given by the formula: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference point.
Atmospheric pressure varies over Earth's surface, mainly due to differences in temperature, altitude, and weather conditions. This variation in air pressure creates different weight of air known as atmospheric weight.