20kg
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Another contributor jumped in:
The man's mass doesn't change. He carries 50 kg with him wherever he goes.
But his weight changes, depending on the acceleration of gravity where he is.
Weight = (mass) times (acceleration of gravity).
So we need to find the acceleration of gravity at 2 radii above the surface.
The acceleration of gravity is proportional to the square of the distance from the
place to the center of the earth, and on the surface, it's 9.8 m/s2 .
On the surface, you're 1 radius from the center. At 2 radii from the surface, you're
2 more radii from the center, or 3 radii all together. So your distance from the center
has tripled.
The acceleration of gravity is 1/32 of its original value, or 1/9th of 9.8 .
9.8/9 = 1.089 m/s2 at that position in space.
The man's weight is (mass) times (acceleration of gravity).
On the surface, he weighs (50 x 9.8) = 490 newtons (110.2 pounds).
Out there at 3 radii from the center, he weighs (50 x 1.089) = 54.4 newtons (12.25 pounds).
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BSA = 0.007184 x Weight (kg)^0.425 x Height (cm)^0.725
There is no weight ratio for height. The weight of an object depends on its the volume and density. The volume depends on the height as well as the average cross section so height, alone, cannot determine weight.
It is pounds. An inch is the measuring unit for height. A pound is the measuring unit for weight. The logic is as follows. height, weight -> (measuring unit for height), (measuring unit for weight) Some similar examples, If it were "height, distance and inches." the missing word would be "miles" If it were "height, age and inches." the missing word would be "years"
Weight*Height Mass*9.8*Height \
Weight = mg (mass x gravity).