Aglebra 2? Yes.
for a palabara, the maximum is the U upside down, the tip of the U. The Bottom of the U the right way is the min,
Yes
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
maximum and minimum are both (-b/2a , c - (b^2/4a))
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
Quadratic functions, represented in the form ( f(x) = ax^2 + bx + c ), are useful for solving maximum and minimum problems due to their parabolic shape. The vertex of the parabola indicates the maximum or minimum value, depending on whether the parabola opens upwards (minimum) or downwards (maximum). By finding the vertex using the formula ( x = -\frac{b}{2a} ), we can efficiently determine these extrema, making quadratic functions invaluable in optimization problems.
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
Yes
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
The vertex.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
maximum and minimum are both (-b/2a , c - (b^2/4a))
Apex.
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
vertex
It can't - unless you analyze the function restricted to a certain interval.
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
They are simply referred to as local minimums and maximums. Experience: Algebra 2 Advanced