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∙ 7y ago8.47992684×1013
Vanessa Middleton
Answer assuming that by 'football' you meant one used for soccer: Volume of a sphere (the football) = 4/3*pi*radius3 Surface area of a sphere = 4*pi*radius2 -------------------------------- Answer assuming that by 'football' you meant one used for American football: Using the dimensions given on Wikipedia for a standard American football (length of ~11 inches and a central circumference of ~22 inches), one can see that the central radius is approximately 3.5 inches. Further assuming that the shape of an American football in long cross-section is roughly that of a Vesica Piscis, one can integrate using the curve produced to yield either surface area or volume contained. Such integrations are particularly easy and straight forward to perform using a numerical approach such as by using a spreadsheet application, like Microsoft Excel. The approximate volume and surface area of a standard football are 232 cubic inches and 189 square inches, respectively. If one wanted to make a rough empirical check of this volume calculation, a properly inflated standard football could be immersed in water and the the displacement carefully measured. Checking the surface area would involve a bit more work but could be accomplished, again roughly, by deflating the ball and cutting it into triangular pieces that individually lie flat; which could then be measured and their collective surface areas summed up.
A square yard covers, well, one square yard of ground. One could also say it covers nine square feet, or 1,296 square inches. A square yard is a measurement of area. It is not a measurement of the actual surface.
The description given could be applicable to a pyramid
Area. Area is measured by two lengths multiplied together, so any square-shaped area would be measured in a square (length) area. For example houses could be measured in square feet, landscapes could be measured in square miles, something like a small surface might be measured in square centimeters.
To put it one way, its about the distance that you could easily walk in eight minutes or so. Unless you want to try picturing 12 football fields end-to-end, etc. It is also about one kilometer
A standard football field measures 360 feet by 160 feet. There are 27,878,400 feet in a square mile. This means that you could fit a total of 484 standard football fields in a square mile.
A football field is 6400 yd^2, which, in square kilometers, is around 0.0054. 0.8/0.0054 = 148. You could fit 148 football fields into 0.8 km^2
25 football fields can fit inside the pentagon
"36 football fields could fit in side auscgwitz"Um no? A football field is 57600 sqaure feet including the end zones. Auschwitz is approximately 11.7 square miles.100,000,000 square feet is approximately 3.7 square miles. 57600 square feet is0.0020661157 square miles.0.0020661157x=11.7x=5662.8 fields
If you want to get arrested.
15,000 acres is approximately equal to 23.44 square miles. This is roughly equivalent to the size of a mid-sized city, such as Washington D.C. It could also be compared to about 11,400 football fields.
How many football pitches could you fit into the O2 Arena
The surface area of a cylinder is measured in square units, and could be measured in square centimeters.
You could think of it as approximately 7 football fields. Or 7/10ths of a kilometer. Or about how far you could walk in 8 and a half minutes.
tennis, soccer, volleyball, basket ball any thing really depending on how big your yard is
Twenty-five acres is roughly equivalent to 18.84 football fields or 101,376 square yards. Visualizing it can be challenging, but it helps to think of it as a large expanse of land that could accommodate several buildings, a farm, or a sizable park area.
Answer assuming that by 'football' you meant one used for soccer: Volume of a sphere (the football) = 4/3*pi*radius3 Surface area of a sphere = 4*pi*radius2 -------------------------------- Answer assuming that by 'football' you meant one used for American football: Using the dimensions given on Wikipedia for a standard American football (length of ~11 inches and a central circumference of ~22 inches), one can see that the central radius is approximately 3.5 inches. Further assuming that the shape of an American football in long cross-section is roughly that of a Vesica Piscis, one can integrate using the curve produced to yield either surface area or volume contained. Such integrations are particularly easy and straight forward to perform using a numerical approach such as by using a spreadsheet application, like Microsoft Excel. The approximate volume and surface area of a standard football are 232 cubic inches and 189 square inches, respectively. If one wanted to make a rough empirical check of this volume calculation, a properly inflated standard football could be immersed in water and the the displacement carefully measured. Checking the surface area would involve a bit more work but could be accomplished, again roughly, by deflating the ball and cutting it into triangular pieces that individually lie flat; which could then be measured and their collective surface areas summed up.