Number of possible total pairs = 36
Number of pairs which give five as a sum = {1,4},{2,3},{3,2},{4,1}
So, P(Sum=5) = 4/36 = 1/9
The probability to get a 12, with two dice, is 1/36.
Prob = 4/36 = 1/9
7
The probability is 1/36.
If the order of the dice is irrelevant, then the answer is 21. If the order of the dice is relevant, the answer is 36.
The probability to get a 12, with two dice, is 1/36.
If the dice are fair then it is 5/36.
It is 1/9.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
Prob = 4/36 = 1/9
6/36 which is equal to 1/6
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
7
The probability is 1/36.
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".