Prob = 4/36 = 1/9
The probability to get a 12, with two dice, is 1/36.
The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.
The probability of any event MUST be a number between 0 and 1. It is not possible to have a probability of 18 or 16. Furthermore, given that the dice are not normal, the question should also specify how many faces they have and what numbers are on these faces.
You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all. Of these the first four are favourable outcomes (sum < 9) So the required probability is 4/6 or 2/3
Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).
It is 1/9.
If the dice are fair then it is 5/36.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The probability to get a 12, with two dice, is 1/36.
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.
The probability of any event MUST be a number between 0 and 1. It is not possible to have a probability of 18 or 16. Furthermore, given that the dice are not normal, the question should also specify how many faces they have and what numbers are on these faces.
A sum that is a factor of 6 has a greater probability.to my dick
You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all. Of these the first four are favourable outcomes (sum < 9) So the required probability is 4/6 or 2/3
There are a total of 12 faces on a pair of dice.