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∙ 12y agothe answer is 24-9 m/sec. yuor welcome
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∙ 12y agoA freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
Data is insufficient. initial velocity is 0. final velocity is 30 mph. Need acceleration to use the formula v = u + at.
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
The change in velocity of a falling object is calculated by subtracting the initial velocity from the final velocity. The acceleration due to gravity is typically involved in this calculation. The formula for calculating the change in velocity is: change in velocity = final velocity - initial velocity.
The initial velocity of the ball can be calculated using the kinematic equation: v = u - gt, where v is the final velocity (0 m/s at the top of the motion), u is the initial velocity, g is the acceleration due to gravity (9.81 m/s^2), and t is the time taken to reach the top (3.0 seconds). Solving for u, the initial velocity is approximately 29.43 m/s.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
To find the velocity attained by the rocket, we can use the equation: velocity = initial velocity + (acceleration x time) First, calculate the acceleration using Newton's second law: acceleration = force / mass = 5 x 10^5 N / 2 x 10^4 kg = 25 m/s^2 Next, plug the acceleration and time (20 seconds) into the formula to find the final velocity: velocity = 0 + (25 m/s^2 x 20 s) = 500 m/s.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
l2Math. l2Math.
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.