the answer is 24-9 m/sec. yuor welcome
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
Data is insufficient. initial velocity is 0. final velocity is 30 mph. Need acceleration to use the formula v = u + at.
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
The speed (magnitude of velocity) is always 9.8 meters per second (32.2 feet per second) greater than it was exactly one second earlier. If the object spent "N" seconds falling, then its speed (magnitude of velocity) is 9.8N meters per second (32.2N feet per second) greater at the bottom than it was at the top. The direction of velocity remains constant under the influence of gravity ... straight down.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
The initial velocity of the ball can be calculated using the kinematic equation: v = u - gt, where v is the final velocity (0 m/s at the top of the motion), u is the initial velocity, g is the acceleration due to gravity (9.81 m/s^2), and t is the time taken to reach the top (3.0 seconds). Solving for u, the initial velocity is approximately 29.43 m/s.
To find the velocity attained by the rocket, we can use the equation: velocity = initial velocity + (acceleration x time) First, calculate the acceleration using Newton's second law: acceleration = force / mass = 5 x 10^5 N / 2 x 10^4 kg = 25 m/s^2 Next, plug the acceleration and time (20 seconds) into the formula to find the final velocity: velocity = 0 + (25 m/s^2 x 20 s) = 500 m/s.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
To calculate the braking time from 1.5 to 2 seconds, we need to know the initial velocity and the acceleration of the object. The final velocity can be determined using the formula: final velocity = initial velocity + (acceleration * time). If we have this information, we can plug in the values to find the final velocity at 2 seconds.
l2Math. l2Math.
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.