On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get:
78.4m/s
To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.
19.6 meters / 64.4 ft
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
To determine how long it takes for the cricket to land back on the ground after jumping with an initial vertical velocity of 4 ft per second, we can use the formula for the time of flight in projectile motion. The time to reach the maximum height is given by ( t = \frac{v}{g} ), where ( v ) is the initial velocity and ( g ) is the acceleration due to gravity (approximately 32 ft/s²). In this case, it takes ( t = \frac{4}{32} = 0.125 ) seconds to reach the peak. Since the time to ascend and descend is equal, the total time until the cricket lands back on the ground is ( 2 \times 0.125 = 0.25 ) seconds.
The velocity of a falling object increases as it falls due to the acceleration of gravity acting on it. As the object falls, it gains speed and accelerates toward the ground until it reaches a constant velocity known as terminal velocity.
Perhaps you mean terminal velocity. This is the maximum velocity reached by an object falling to the ground when the acceleration due to gravity is matched by the drag resistance of the air through which it is falling.
The velocity of the penny as it hits the ground can be calculated using the equation: velocity = distance/time. Assuming the penny falls vertically, if we take the distance it falls to be 9.8 m/s^2 x (4.5 s)^2 / 2 ≈ 99.22 meters and the time is 4.5 seconds, the velocity would be 99.22 meters / 4.5 seconds = 22.04 m/s.
Any change in the velocity of anything is known as 'acceleration'. In the case of a falling object near the Earth's surface, the direction of the velocity is constant, and its magnitude increases by 9.8 meters (32.2 feet) per second, every second.
To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.
A apple falling to the ground IS an apple falling to the ground.
The velocity of free falling bodies does change due to gravity accelerating them towards the ground. However, in the absence of air resistance, the acceleration due to gravity causes the velocity to increase at a constant rate, resulting in a uniform change in speed over time. This creates the perception that the velocity is not changing, but in reality, it is increasing continuously.
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
19.6 meters / 64.4 ft
In a vacuum (i.e. neglecting air resistance) a falling object would reach a speed of about 124.2 m/s (278 mph) in falling 828 m. However, in an average configuration, a coin would reach terminal velocity at about 18.7 m/s (42 mph) and take approximately 45 seconds to reach the ground from 828 m. Edge on, it could reach 29 m/sec (65 mph) and be on the ground in just 31 seconds. Note that you cannot drop a coin straight down, but would have to throw it outward a distance of at least 15 m (50 feet) to reach the ground. *Base jumpers who jumped from the top of the building (2717 feet) took about 80 seconds to reach the ground including 10 seconds of freefall.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
The impact force depends upon the height from which it has fallen (IE- its velocity upon impact), and the duration of impact (determined by the elasticity of the collision). However, the object exerts no force upon the ground *while* falling.