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What are all the possible dimensions of the rectangle with an area of 54?
To find the possible dimensions of a rectangle with an area of 54, we can consider pairs of factors of 54. The factor pairs are (1, 54), (2, 27), (3, 18), (6, 9). Therefore, the possible dimensions of the rectangle are: 1 by 54, 2 by 27, 3 by 18, and 6 by 9.
What is the perimeter of a rectangle 12 by 14?
Perimeter = 12+12+14+14 = 54 uits of measurement
What are the dimensions of a rectangle with a perimeter of 30 inches and an area of 54 square inches?
Let the length be ( l ) and the width be ( w ). The perimeter is given by the formula ( P = 2(l + w) ), so ( l + w = 15 ). The area is given by ( A = l \times w = 54 ). Solving these equations, we find the dimensions are ( l = 18 ) inches and ( w = 3 ) inches.
The length of rectangle is 6 metre less than the three time its breadth if its perimeter is 148 metre find the dimensions of the rectangle?
Let x = width 3x - 6 = length Perimeter is 2(l + w) 2(x + 3x - 6) 2x + 6x - 12 8x - 12 = 148 8x = 160 x = 20 3x - 6 = 54 Rectangle is 20 x 54 Check it. 2(20 + 54) 2 x 74 = 148 It checks.
What is the length of a rectangle if its width is 9inches and the perimeter is 54 inches?
Perimeter = 2*(Length + Width) 54 = 2*(L + 9) = 2L + 18 So 2L = 54 - 18 = 36 and therefore L = 18 inches.
What is the perimeter of a rectangle if the dimensions are 19 X 8?
54
What are all the possible dimensions of the rectangle with an area of 54?
To find the possible dimensions of a rectangle with an area of 54, we can consider pairs of factors of 54. The factor pairs are (1, 54), (2, 27), (3, 18), (6, 9). Therefore, the possible dimensions of the rectangle are: 1 by 54, 2 by 27, 3 by 18, and 6 by 9.
What is the Perimeter of rectangle that is 9 meters by 18 meters?
54 Meters
If the area of a rectangle is 54 sft,then which is the most suitable perimeter?
30
What is the perimeter of a rectangle 12 by 14?
Perimeter = 12+12+14+14 = 54 uits of measurement
What are the dimensions of a rectangle with a perimeter of 30 inches and an area of 54 square inches?
Let the length be ( l ) and the width be ( w ). The perimeter is given by the formula ( P = 2(l + w) ), so ( l + w = 15 ). The area is given by ( A = l \times w = 54 ). Solving these equations, we find the dimensions are ( l = 18 ) inches and ( w = 3 ) inches.
The width of a rectangle is one half its length the perimeter of the rectangle is 54 cm what are the width and length of the rectangle?
width=9 length=18
The length of rectangle is 6 metre less than the three time its breadth if its perimeter is 148 metre find the dimensions of the rectangle?
Let x = width 3x - 6 = length Perimeter is 2(l + w) 2(x + 3x - 6) 2x + 6x - 12 8x - 12 = 148 8x = 160 x = 20 3x - 6 = 54 Rectangle is 20 x 54 Check it. 2(20 + 54) 2 x 74 = 148 It checks.
What is the perimeter of rectangle with an area of 54 square feet?
This has several values.The perimeter is twice the sum of any two numbers whose product is 54.
What is the area and perimeter rectangle 6 cm x 9 cm?
Area: 54 square cm Perimeter: 30 cm
What is the length of a rectangle if its width is 9inches and the perimeter is 54 inches?
Perimeter = 2*(Length + Width) 54 = 2*(L + 9) = 2L + 18 So 2L = 54 - 18 = 36 and therefore L = 18 inches.
The perimeter of a rectangle is 240 feet and Its length is 12 less than it's width what are the dimensions of the rectangle?
Let the length be x-12 and the width be x: 2(length+width) = perimeter 2(x-12+x) = 240 2x-24+2x = 240 4x = 240+24 4x = 264 x = 66 Therefore: length = 54 feet and width = 66 feet
