Let the length be ( l ) and the width be ( w ). The perimeter is given by the formula ( P = 2(l + w) ), so ( l + w = 15 ). The area is given by ( A = l \times w = 54 ). Solving these equations, we find the dimensions are ( l = 18 ) inches and ( w = 3 ) inches.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
That is not a square, it is a rectangle and it has a perimeter of 36 inches.
28 inches
There is no limit to the size of the perimeter.
Its dimensions are 6 inches by 7 inches because 2(6+7)=26 inches and 6*7=42 square inches
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
That is not a square, it is a rectangle and it has a perimeter of 36 inches.
The perimeter is 35.78 inches.
28 inches
12 square feet.
There is no limit to the size of the perimeter.
If the perimeter of a rectangle is 16 inches, the formula for the perimeter is ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting the perimeter equal to 16 gives us ( l + w = 8 ). The area ( A ) of the rectangle is calculated as ( A = l \times w ). Without specific dimensions for length and width, the area can vary; however, the maximum area occurs when the rectangle is a square with each side measuring 4 inches, giving an area of ( 16 ) square inches.
Length = 9 Width = 9 Your rectangle is a square.