Q: A round vessel of greater length than breadth and bulging in the middle made of staves and bound with hooops?

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No, but language implies it.

Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 â‰¤ L < 30 cm will do. Then breadth, B = 30 - L cm.

Add the length and breadth and then double it.

what is the pressure if the length is 16cm & breadth is 7cm

The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).

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Perimeter = 2*(Length + Breadth) So, 1570 = 2*(168 + Breadth) 785 = 168 + Breadth Breadth = 617 metres Which is rather an unusual result because normally the length is greater than the breadth.

Usually, yes.

No, but language implies it.

2(length+breadth)=Perimetre Length= (Perimetre/2)-Breadth Area=Length x breadth

breadth

Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 â‰¤ L < 30 cm will do. Then breadth, B = 30 - L cm.

length is 3 and breadth is 2

If the shape is a rectangle (or square), then Perimeter = 2*(Length + Breadth) So Breadth = Perimeter/2 - Length

Add the length and breadth and then double it.

what is the pressure if the length is 16cm & breadth is 7cm

The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).

Length (breadth, width or height are also used).Length (breadth, width or height are also used).Length (breadth, width or height are also used).Length (breadth, width or height are also used).