Wiki User
∙ 14y agoIt depends on the underlying distribution. If Gaussian (standrad normal) then the percentile is 77.
Wiki User
∙ 14y agoapproximately 32nd percentile
The top percentile is 100. It represents the maximum score.
The 95th percentile represents an IQ of about 125.
The Miller Analogies Test scores have a mean of 400 and a standard deviation of 25, and are approximately normally distributed.z = ( 351.5 - 400 ) / 25 = -1.94That's about the 2.6 percentile.(Used wolframalpha.com with input Pr [x < -1.94] with x normally distributed with mean 0 and standard deviation 1.)
It is -1.281551
approximately 32nd percentile
124
The top percentile is 100. It represents the maximum score.
To find what z-score represents the 80th percentile, simply solve for 0.8 = F(z), where F(x) is the standard normal cumulative distribution function. Solving gives us: z = 0.842
The 95th percentile represents an IQ of about 125.
The Miller Analogies Test scores have a mean of 400 and a standard deviation of 25, and are approximately normally distributed.z = ( 351.5 - 400 ) / 25 = -1.94That's about the 2.6 percentile.(Used wolframalpha.com with input Pr [x < -1.94] with x normally distributed with mean 0 and standard deviation 1.)
The standardised score decreases.
2.326
It is -1.281551
T-score is used when you don't have the population standard deviation and must use the sample standard deviation as a substitute.
score of 92
Answer: 0 The z score is the value of the random variable associated with the standardized normal distribution (mean = 0, standard deviation =1). Now, the median and the mean of a normal distribution are the same. The 50 percentile z score = the median = mean = 0.