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∙ 14y agoThe formula is C/T, where C is the change, and T is the time to take this change.
Thus, we can plug in the values as such: 25/30 = 5/6
(0.8(3)) is also a proper answer.
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∙ 14y agoRule: Magnitude of acceleration = Change of velocity / Time interval In linear motion, magnitude of acceleration is the measurement of change in speed in speed per unit time. For example: A car reaches a speed of 20 miles per second in 4 seconds, the magnitude of acceleration is 5 miles per second. a = 20 miles/second divided by 4 seconds = 5 miles per second. Acceleration is a vector, which means it has magnitude and direction. To describe accelerated motion completely, the direction also needs to be included. So it would be 5 miles per second in whatever direction it is going.
Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------
-6.667 miles per second squared
3 / 12 = 0.25 miles/second2.
Acceleration = (change in speed) divided by (time for the change)Acceleration = (25 - 0)/(3) = 81/3 miles per second2Don't try this at home. That acceleration is about 1,368 G's. You can not survive it!
-66.667 miles per second squared
Rule: Magnitude of acceleration = Change of velocity / Time interval In linear motion, magnitude of acceleration is the measurement of change in speed in speed per unit time. For example: A car reaches a speed of 20 miles per second in 4 seconds, the magnitude of acceleration is 5 miles per second. a = 20 miles/second divided by 4 seconds = 5 miles per second. Acceleration is a vector, which means it has magnitude and direction. To describe accelerated motion completely, the direction also needs to be included. So it would be 5 miles per second in whatever direction it is going.
Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------
After 15 seconds, the train's speed would be 7.5 miles per second. This can be calculated by multiplying the acceleration (0.5 miles per second) by the time (15 seconds).
The acceleration of the car can be calculated using the formula: acceleration = change in velocity / time. In this case, the change in velocity is 20 - 5 = 15 miles per second. So, the acceleration is 15 miles per second / 3 seconds = 5 miles per second squared.
A gain of 2 miles per second squared
20 miles per second / 10 seconds = 2 miles per second ^ 2
To calculate acceleration in miles per hour per second, first convert the acceleration from 0 to 60 mph in 3 seconds to miles per hour. 60 mph / 3 sec = 20 mph/sec. So, the acceleration in miles per hour per second is 20 mph/sec.
negative one mile per second per second
-6.667 miles per second squared
3 / 12 = 0.25 miles/second2.
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.