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Let the land distance travelled be d km

Let the speed of the plane in still air be s km/h

time = distance / speed

On the first flight: 4.32 hr = d km / (s + 25.5) km/h → d km = 4.32 × (s + 25.5) km

On the second flight: 4.97 hr = d km / (s - 25.5) km/h → d km = 4.97 × (s - 25.5) km

→ 4.32 × (s + 25.5) = 4.97 × (s - 25.5)

→ 4.32s + 25.5 × 4.32 = 4.97s - 25.5 × 4.97

→ 4.97s - 4.32s = 4.97 × 25.5 + 4.32 × 25.5

→ (4.97 - 4.32)s = 25.5 × (4.97 + 4.32) × 25.5

→ s = 25.5 × (4.97 + 4.32)/(4.97 - 4.32) ≈ 364.45 km/h

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