Wiki User
∙ 11y agoYou haven't asked a question. So I'll ask one using your data,
and then answer it.
Q:
What is the apparent weight of the object when it's completely submerged ?
A:
5 N.
Wiki User
∙ 11y agoIf the object is irregular the best way is to measure the volume of water it displaces when you immerse it completely in water.
You can measure the volume of an object. By putting some water in a container with graduation marks, taking a measurement of the volume of water, then placing the object in the water so that it is totally submerged in the water, then measuring the new volume level. The difference between the new volume and original volume will be the amount of water that the object displaces (or the object's volume).
It's called displacement. Say you have a closed irregular object. It takes up space. Dunk it in water and it displaces the water. Finding out how much water was displaced tells you how much space the object took up. That's the volume =P.
1,500 mL
The volume of an object can be determined by the displacement of water. By dropping the object into a measuring container of water, where the volume of the water is known, the object's volume can then be calculated by subtracting the volume of the water by the volume of the water and object combined.
The volume of water an object displaces is equal to the volume of the object itself, as stated by Archimedes' principle. This principle explains that the volume of fluid displaced by an object immersed in a fluid is equal to the volume of the object.
If the volume of liquid the object displaces weighs more than the object, the object will float. The principle is buoyancy or specific gravity.
"Displacement" means pushing the water away from space where the object wants to be. If 16.5 mL of water is displaced, then the volume of the object must be 16.5 mL. At least the volume of the part of it that's down in the water, like if it's floating.
A submerged object displaces a volume of water that is equal to its own volume. This is known as Archimedes' principle.
The volume of an irregularly shaped geometric object is typically determined by the amount of water it displaces when submerged. This method utilizes the principle of fluid displacement to calculate the volume of the object. By measuring the amount of water the object displaces, one can determine its volume.
If it displaces 8 ml of water then its its volume is equal to the volume of water it displaces, 8 ml or 8 cubic centimeters
652 cm³
If the object is irregular the best way is to measure the volume of water it displaces when you immerse it completely in water.
The mass of an object does not directly affect the amount of water it displaces. The volume of water displaced is determined by the volume of the object that is submerged in the water, regardless of its mass. Archimedes' principle states that the buoyant force (or weight of the water displaced) is equal to the weight of the object, not its mass.
The object will sink because its weight is greater than the weight of the water it displaces. According to Archimedes' principle, the buoyant force acting on an object is equal to the weight of the fluid displaced, so if the object weighs more than the water it displaces, it will not be able to float.
The volume of the object is 652 ml.
No, a body totally submerged in a liquid displaces a volume of water equal to its own volume. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the fluid displaced by that object.