To identify the vertex and axis of symmetry of the parabola represented by the function ( y = 2(x + 2)^2 - 5 ), we can see that it is in vertex form ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex. Here, the vertex is ((-2, -5)) and the axis of symmetry is the vertical line ( x = -2 ).
To find the y-intercept, set ( x = 0 ):
( y = 2(0 + 2)^2 - 5 = 2(4) - 5 = 8 - 5 = 3 ).
Thus, the y-intercept is ( (0, 3) ).
To graph the function ( f(x) = x^2 - 4 ), first identify its key features. This is a quadratic function with a vertex at ( (0, -4) ) and opens upwards. The x-intercepts can be found by setting ( f(x) = 0 ), leading to ( x^2 - 4 = 0 ), or ( x = \pm 2 ). The y-intercept is at ( (0, -4) ), and the graph will be a parabola with symmetry about the y-axis.
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
Yes, it does.
Yes
Yes, but a parabola, itself, can have only a vertical line of symmetry.
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
To graph the function ( f(x) = x^2 - 4 ), first identify its key features. This is a quadratic function with a vertex at ( (0, -4) ) and opens upwards. The x-intercepts can be found by setting ( f(x) = 0 ), leading to ( x^2 - 4 = 0 ), or ( x = \pm 2 ). The y-intercept is at ( (0, -4) ), and the graph will be a parabola with symmetry about the y-axis.
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
Its extremum is on its axis of symmetry.
Yes, it does.
Yes
The graph of a quadratic function is a parabola. It can open either upward or downward depending on the sign of the coefficient of the squared term; if it is positive, the parabola opens upward, and if negative, it opens downward. The vertex of the parabola is its highest or lowest point, and the axis of symmetry is a vertical line that runs through this vertex.
Yes, but a parabola, itself, can have only a vertical line of symmetry.
The shape of the graph of the quadratic function ( y = ax^2 ) is a parabola. If the coefficient ( a ) is positive, the parabola opens upwards, while if ( a ) is negative, it opens downwards. The vertex of the parabola is its highest or lowest point, depending on the direction it opens. The axis of symmetry is the vertical line that passes through the vertex, dividing the parabola into two mirror-image halves.
Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).
The axis of symmetry of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. To find the corresponding (y)-coordinate, substitute the axis of symmetry value back into the quadratic function.
Yes. An ellipse (oval) has two lines of symmetry, but not a rotational symmetry. A parabola has one line and no rotation.