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What is the pythagorean triple of 16-30-34?
8, 15, 17
Which are Pythagorean Triples '8 16 17' '25 60 72.4' '25 60 65' '7 12 14.1' '5 12 13' '16 30 34'?
The combination 5, 12 and 13 is a Pythagorean triple.
What is the hypotenuse if legs are 16 and 30?
To find the length of the hypotenuse of a right triangle, use the Pythagorean Theorem: A2 + B2 =C2Where A and B are the lengths of the legs, and C is the length of the hypotenuse.(16)2+(30)2=C2C=sqrt(256+900)C=34
If the diagonal is 34 and the length is 30 what is the width?
16
30 squared plus 16 squared equals x squared?
30 squared is 900. 16 squared 256. add them and you get 1156. Now, simply do: √1156 The answer is 34. Its simple: (30•30)+(16•16)=x^2 900+256=x^2 1156=x^2 √1156=x 34=x
What is the pythagorean triple of 16 30?
34
What is the pythagorean triple of 16-30-34?
8, 15, 17
Which are Pythagorean Triples '8 16 17' '25 60 72.4' '25 60 65' '7 12 14.1' '5 12 13' '16 30 34'?
The combination 5, 12 and 13 is a Pythagorean triple.
What is the hypotenuse if legs are 16 and 30?
To find the length of the hypotenuse of a right triangle, use the Pythagorean Theorem: A2 + B2 =C2Where A and B are the lengths of the legs, and C is the length of the hypotenuse.(16)2+(30)2=C2C=sqrt(256+900)C=34
Which choiceshows 4x square -30 equals 34?
4x2-30 = 34 4x2 = 34+30 4x2 = 64 x2 = 16 x = 4
Can the sides of a right triangle be 16 30 and 34 in?
To test use PYTHAGORAS ; h^2 = a^2 + b^2 34' is the longest side (h) , hence 34^(2) = 1156 a & b are 16 & 30 Hence 16^() + 30^(2) = 256 + 900 = 1156 , which equatres with 34^(2) . Thereby satisfies the Pythagorean Equation. Hence it is a Right angled triangle. So the sides 16,30, & 34 form a right triangle.
If the diagonal is 34 and the length is 30 what is the width?
16
30 squared plus 16 squared equals x squared?
30 squared is 900. 16 squared 256. add them and you get 1156. Now, simply do: √1156 The answer is 34. Its simple: (30•30)+(16•16)=x^2 900+256=x^2 1156=x^2 √1156=x 34=x
What is equivalent to 34?
assuming 34 means 3/4 12/16 30/40 333/444 and so on ...
When two sides of an isosceles triangle are 34 and the height is 30 what is the base's length?
The length is 32. Since an isosceles triangle is symmetrical, the height divides it into two right triangles. The hypotenuse of one of these triangles is 34, one of the legs is 30 (the height), and the other leg is half of the base, which we'll call x. Using the Pythagorean Theorem, we know x^2+30^2=34^2, or x^2+900=1156. This gives us x^2=256, or x=16 (it could also be -16, but this is absurd because it's a length). We said x was half the base, so the base itself is 2x=2*16=32.
What is the diagonal measurement of a 30 'x 16' rectangle?
That would be 34 feet.
Can 16 30 and 34 be a triangle leangth?
No. But they can be the lengths (not leangths!) of the three sides.
