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It is 0.5d or d/2.
D = D. + V.T + (AT^2)/2(AT^2)/2 = D - D. - V.TAT^2 = 2 (D - D. -V.T)A = [2 (D - D. - V.T)] / T^2D is the Final DisplacementD. is Initial DisplacementV. is Initial VelocityA is AccelerationT is Time
-12
You can write this as:(d+2)/6
No, it is a 3-d shape. A circle is a 2-d shape.