It is 0.5d or d/2.
D = D. + V.T + (AT^2)/2(AT^2)/2 = D - D. - V.TAT^2 = 2 (D - D. -V.T)A = [2 (D - D. - V.T)] / T^2D is the Final DisplacementD. is Initial DisplacementV. is Initial VelocityA is AccelerationT is Time
-12
You can write this as:(d+2)/6
No, it is a 3-d shape. A circle is a 2-d shape.
d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-1 d-0 a-3 a-2 a-1 a-0 d-3 d-2 d-1 d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-0 a-0 d-1 d-2 d-0 a-3(2) (2)=2 beats [half note] the rest are 1 beat [quarter note] d= the string on the violin (g,d,a,e) -0=how many fingers you put on that string hope this helps!!!!!! >_< hehe...... =P
It is 0.5d or d/2.
D = D. + V.T + (AT^2)/2(AT^2)/2 = D - D. - V.TAT^2 = 2 (D - D. -V.T)A = [2 (D - D. - V.T)] / T^2D is the Final DisplacementD. is Initial DisplacementV. is Initial VelocityA is AccelerationT is Time
-12
1
For (2,1) & ( 14,6) Use Pythagoras. d^2 = (2 - 14)^2 + ( 1 - 6)^2 d^2 = (-12)^2 + (-5)^2 d^2 = 144 + 25 d^2 = 169 d = sqrt(169) d = 13
10 Units.
2 n in a d is 2 = nickels in a dime.
You can write this as:(d+2)/6
No, it is a 3-d shape. A circle is a 2-d shape.
-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
2-D means 2 dimensions.