No, there are not, and here's why: to solve for this kind of problem, you will need to set both equations equal to each other. This will give you y - 5x + 2 = y - 5x - 3, You can subtract a y and a -5x from both sides, and this will leave you with 2 = -3, which is, of course, an impossibility. There are therefore no solutions to these inequalities.
Systems of inequalities in n variables with create an n-dimensional shape in n-dimensional space which is called the feasible region. Any point inside this region will be a solution to the system of inequalities; any point outside it will not. If all the inequalities are linear then the shape will be a convex polyhedron in n-space. If any are non-linear inequalities then the solution-space will be a complicated shape. As with a system of equations, with continuous variables, there need not be any solution but there can be one or infinitely many.
A system of equations can have any number of inequalities.
No because the discriminant is less than zero.
Just one.
It needs to have an equality or equality signs to have solutions for it.Without any equality signs the given expression can't be considered to be an equation although it might be possible to simplify it.
Systems of inequalities in n variables with create an n-dimensional shape in n-dimensional space which is called the feasible region. Any point inside this region will be a solution to the system of inequalities; any point outside it will not. If all the inequalities are linear then the shape will be a convex polyhedron in n-space. If any are non-linear inequalities then the solution-space will be a complicated shape. As with a system of equations, with continuous variables, there need not be any solution but there can be one or infinitely many.
An inequality determines a region of space in which the solutions for that particular inequality. For a system of inequalities, these regions may overlap. The solution set is any point in the overlap. If the regions do not overlap then there is no solution to the system.
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
A system of equations can have any number of inequalities.
no
No because the discriminant is less than zero.
Just one.
It needs to have an equality or equality signs to have solutions for it.Without any equality signs the given expression can't be considered to be an equation although it might be possible to simplify it.
In 2-dimensional space, an equality could be represented by a line. A set of equalities would be represented by a set of lines. If these lines intersected at a single point, that point would be the solution to the set of equations. With inequalities, instead of a line you get a region - one side of the line representing the corresponding equality (or the other). The line, itself, may be included or excluded. Each inequality can be represented by a region and, if these regions overlap, any point within that sub-region is a solution to the system of inequalities.
Quite often, it has infinitely many solutions. For example: x > 5 Any number greater than 5 will work here. It need not even be a whole number. It is also possible for an equation involving inequalities to have one or no solution. For instance: x squared < 0 Has zero solutions (at least, in the set of real numbers).
Without any equality signs the given expressions can't be considered to be simultaneous equations and so therefore no solutions are possible.
Strictly speaking the above equation is a tautological equation or an IDENTITY. An identity is true for all values of any variables that appear in it. Thus, the above "equation" is true for all value of x. - that is, it has infinitely many solutions.