No, there are not, and here's why: to solve for this kind of problem, you will need to set both equations equal to each other. This will give you y - 5x + 2 = y - 5x - 3, You can subtract a y and a -5x from both sides, and this will leave you with 2 = -3, which is, of course, an impossibility. There are therefore no solutions to these inequalities.
Systems of inequalities in n variables with create an n-dimensional shape in n-dimensional space which is called the feasible region. Any point inside this region will be a solution to the system of inequalities; any point outside it will not. If all the inequalities are linear then the shape will be a convex polyhedron in n-space. If any are non-linear inequalities then the solution-space will be a complicated shape. As with a system of equations, with continuous variables, there need not be any solution but there can be one or infinitely many.
In a graph of a system of two linear inequalities, the doubly shaded region represents the set of all points that satisfy both inequalities simultaneously. Any point within this region will meet the criteria set by both linear inequalities, meaning its coordinates will fulfill the conditions of each inequality. Consequently, this region illustrates all possible solutions that satisfy the system, while points outside this region do not satisfy at least one of the inequalities.
No because the discriminant is less than zero.
A system of equations can have any number of inequalities.
Just one.
Systems of inequalities in n variables with create an n-dimensional shape in n-dimensional space which is called the feasible region. Any point inside this region will be a solution to the system of inequalities; any point outside it will not. If all the inequalities are linear then the shape will be a convex polyhedron in n-space. If any are non-linear inequalities then the solution-space will be a complicated shape. As with a system of equations, with continuous variables, there need not be any solution but there can be one or infinitely many.
An inequality determines a region of space in which the solutions for that particular inequality. For a system of inequalities, these regions may overlap. The solution set is any point in the overlap. If the regions do not overlap then there is no solution to the system.
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
no
A system of equations can have any number of inequalities.
No because the discriminant is less than zero.
Just one.
It needs to have an equality or equality signs to have solutions for it.Without any equality signs the given expression can't be considered to be an equation although it might be possible to simplify it.
Quite often, it has infinitely many solutions. For example: x > 5 Any number greater than 5 will work here. It need not even be a whole number. It is also possible for an equation involving inequalities to have one or no solution. For instance: x squared < 0 Has zero solutions (at least, in the set of real numbers).
In 2-dimensional space, an equality could be represented by a line. A set of equalities would be represented by a set of lines. If these lines intersected at a single point, that point would be the solution to the set of equations. With inequalities, instead of a line you get a region - one side of the line representing the corresponding equality (or the other). The line, itself, may be included or excluded. Each inequality can be represented by a region and, if these regions overlap, any point within that sub-region is a solution to the system of inequalities.
Without any equality signs the given expressions can't be considered to be simultaneous equations and so therefore no solutions are possible.
Strictly speaking the above equation is a tautological equation or an IDENTITY. An identity is true for all values of any variables that appear in it. Thus, the above "equation" is true for all value of x. - that is, it has infinitely many solutions.