Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b
A+A*b does not mean A plus Ab the operation signified by "+" is called "or" the operation signified by "*" is called "and" there are four possible outcomes of a+a*b if a=1 and b=1 the result is 1 if a=1 and b=0 the result is 1 if a=0 and b=1 the result is 0 if a=0 and b=0 the result is 0 a+a*b is 1 if a is 1 and a+a*b is 0 if a is 0 regardless of the value of b thus a+a*b=a Q.E.D.
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
input outA B A XNOR B 0 0 1 0 1 0 1 0 0 1 1 1
Yes because if 1+0=1 than 0 plus b equals b
yes
I can assure you, you guys can marry, no problem.
You can marry anyone you want.
A person with A- can marry a person with B+. There are no limitations on marriages based on blodo type.
int gcd (int a, int b) { if (a<0) a= -a; if (b<0) b= -b; while (a!=0 && b!=0 && a!=1 && b!=1) { int tmp; if (a>b) tmp= b, b= a, a= tmp; a= a%b; } if (a==0) return b; else if (b==0) return a; else return 1; }
A*(B-B) = A*0 = 0 Expanding the left hand side, using the distributive property, A*B + A*(-B) = 0 That is, A*B and A*(-B) are additive inverses. Next, (A-A)*(-B) = 0*(-B) = 0 Expanding, A*(-B) + (-A)*(-B) = 0 Therefore A*(-B) and (-A)*(-B) are additive inverses But, from above, the additive inverse of -A*B is A*B Therefore (-A)*(-B) = A*B It is not known when this was proven.
Yes, of course! Depending on the girl's underlying genetics the children will be either blood type 0 or B, rhesus factor positive or (rarely) negative.
Cardi B married to Offset in 2017
Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.
Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b
A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C
nobody