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How can you prove if a and b are real numbers then a plus b-a equals b?
Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b
Prove A plus Ab equals A using boolean algebra theorem?
A+A*b does not mean A plus Ab the operation signified by "+" is called "or" the operation signified by "*" is called "and" there are four possible outcomes of a+a*b if a=1 and b=1 the result is 1 if a=1 and b=0 the result is 1 if a=0 and b=1 the result is 0 if a=0 and b=0 the result is 0 a+a*b is 1 if a is 1 and a+a*b is 0 if a is 0 regardless of the value of b thus a+a*b=a Q.E.D.
3b2 plus b-10 equals 0?
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
CAN 0 plus equals B plus equals B?
Yes because if 1+0=1 than 0 plus b equals b
When A 0 B 0 C 1 then in 2 input logic gate you get - - gate?
input outA B A XNOR B 0 0 1 0 1 0 1 0 0 1 1 1
