In the context of marriage laws, if "B" and "0" refer to individuals, then yes, they can marry if they meet the legal requirements and consent to the marriage. However, if "0" represents a non-human entity or is used symbolically, then marriage would not be applicable. It's important to clarify the context of "0" to provide a definitive answer.
Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b
A+A*b does not mean A plus Ab the operation signified by "+" is called "or" the operation signified by "*" is called "and" there are four possible outcomes of a+a*b if a=1 and b=1 the result is 1 if a=1 and b=0 the result is 1 if a=0 and b=1 the result is 0 if a=0 and b=0 the result is 0 a+a*b is 1 if a is 1 and a+a*b is 0 if a is 0 regardless of the value of b thus a+a*b=a Q.E.D.
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
Yes because if 1+0=1 than 0 plus b equals b
Yeah! anyone can marry anyone. as long as there in love. having sex however is a different matter
yes
I can assure you, you guys can marry, no problem.
You can marry anyone you want.
A person with A- can marry a person with B+. There are no limitations on marriages based on blodo type.
int gcd (int a, int b) { if (a<0) a= -a; if (b<0) b= -b; while (a!=0 && b!=0 && a!=1 && b!=1) { int tmp; if (a>b) tmp= b, b= a, a= tmp; a= a%b; } if (a==0) return b; else if (b==0) return a; else return 1; }
Cardi B married to Offset in 2017
A*(B-B) = A*0 = 0 Expanding the left hand side, using the distributive property, A*B + A*(-B) = 0 That is, A*B and A*(-B) are additive inverses. Next, (A-A)*(-B) = 0*(-B) = 0 Expanding, A*(-B) + (-A)*(-B) = 0 Therefore A*(-B) and (-A)*(-B) are additive inverses But, from above, the additive inverse of -A*B is A*B Therefore (-A)*(-B) = A*B It is not known when this was proven.
Yes, of course! Depending on the girl's underlying genetics the children will be either blood type 0 or B, rhesus factor positive or (rarely) negative.
Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b
Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.
nobody
me