#define max2(a,b) (b>a?b:a)
#define max3(a,b,c) (max2(a,max(b,c)))
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max = a > b ? a : b; max = max > c ? max : c;
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
94+95+96 96
They are: 83, 89 and 97
43