max = a > b ? a : b; max = max > c ? max : c;
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
94+95+96 96
They are: 83, 89 and 97
43
max = a > b ? a : b; max = max > c ? max : c;
program that take three decimal number as input and find the largest among them in assembly language
R = (A > B && A > C) ? A : (B > C) ? B : C; // parentheses not necessary - for clarity only
largest of a, b, c :a > b ? a > c ? a : c : b > c ? b : c
start input A & B if A>B print A is greatest if B>A print B is greatest stop james ola writes.....SOT.
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
To find the largest of three numbers, first find the largest of two numbers: int max (int x, int y) { return x<y?y:x; } Now you can use this one function to find the largest of three numbers: int max (int x, int y, int z) { return max (max (x, y), z); }
write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
94+95+96 96
998
0.31 is the largest of those three numbers.
Step1- Read a,b,c. Step2-if a>b continue step 5. Step3- b>c then print “b is the largest " and continue step 7. Step4- continue step 6 Step5-if a>c then print “a is the largest " then continue step7. Step6- print “z is largest". Step7- end.