#define max2(a,b) (b>a?b:a)
#define max3(a,b,c) (max2(a,max(b,c)))
max = a > b ? a : b; max = max > c ? max : c;
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
94+95+96 96
They are: 83, 89 and 97
43
max = a > b ? a : b; max = max > c ? max : c;
program that take three decimal number as input and find the largest among them in assembly language
R = (A > B && A > C) ? A : (B > C) ? B : C; // parentheses not necessary - for clarity only
largest of a, b, c :a > b ? a > c ? a : c : b > c ? b : c
start input A & B if A>B print A is greatest if B>A print B is greatest stop james ola writes.....SOT.
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
To find the largest of three numbers, first find the largest of two numbers: int max (int x, int y) { return x<y?y:x; } Now you can use this one function to find the largest of three numbers: int max (int x, int y, int z) { return max (max (x, y), z); }
94+95+96 96
write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
998
0.31 is the largest of those three numbers.
The three common factors of 72, 36, and 24 are 1, 2, and 3. These numbers can divide each of the three values without leaving a remainder. Additionally, the greatest common factor among these numbers is 12, which is the largest of their common factors.