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I can't either. Don't know what a "tan angle" is, so don't know

what I'm looking for. It might be right here under my nose.

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Q: Can't find the tan angle
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How do you find the tangent of a triangle?

that queation doesnt make any sence u retard because u cant get the tan of a triangle u can only get the tan of a number To find the tan of an angle you want to use this ratio: Opposite side divided by adjacent side Once you find the answer, on a scientific calculator you enter in your answer and hit the inv button then the tan button and it should give you your answer.


In math What is the difference between tan and tan-1?

In mathematics, "tan" refers to the tangent function, which calculates the ratio of the opposite side to the adjacent side in a right triangle for a given angle. On the other hand, "tan⁻¹" (or arctan) is the inverse tangent function, which takes a ratio and returns the angle whose tangent is that ratio. Essentially, while tan gives you the tangent of an angle, tan⁻¹ helps you find the angle when you know the tangent value.


What is the height of a building when the distance between its angles of elevation which are 29 degrees and 37 degrees is 30 meters on level ground?

Using trigonometry its height works out as 63 meters to the nearest meter. -------------------------------------------------------------------------------------------------------- let: h = height building α, β be the angles of elevation (29° and 37° in some order) d be the distance between the elevations (30 m). x = distance from building where the elevation of angle α is measured. Then: angle α is an exterior angle to the triangle which contains the position from which angle α is measured, the position from which angle β is measured and the point of the top of the building. Thus angle α = angle β + angle at top of building of this triangle → angle α > angle β as the angle at the top of the building is > 0 → α = 37°, β = 29° Using the tangent trigonometric ratio we can form two equations, one with angle α, one with angle β: tan α = h/x → x = h/tan α tan β = h/(x + d) → x = h/tan β - d → h/tan α = h/tan β - d → h/tan β - 1/tan α = d → h(1/tan β - 1/tan α) = d → h(tan α - tan β)/(tan α tan β) = d → h = (d tan α tan β)/(tan α - tan β) We can now substitute the values of α, β and x in and find the height: h = (30 m × tan 37° × tan 29°)/(tan 37° - tan 29°) ≈ 63 m


What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?

It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft


Find the angle with tangent ratio of 0.4877?

tan-1(0.4877) = 25.99849161 or about 26 degrees