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This is somewhat difficult to explain without images, but here goes: You can use the information given in the problem to draw a right triangle on your coordinate axes. The hypotenuse of this right triangle should extend from the origin to point P and make a 50 degree angle with the x-axis. We'll call this hypotenuse r, which in this case is 1 (because we're dealing with the unit circle). If you extend a line down from point P perpendicular to the x-axis, the segment formed, which we will call y, will be the side of the right triangle opposite the 50 degree angle. The remaining side, x, lies along the x-axis between the origin and the point where side y intercepts the x axis. Recognize that side x and side y represent, respectively, the x and y coordinates of P. These values can be found using trigonometric relationships. Recall that sin(a) = opposite/hypotenuse. In this case, a = 50, the opposite side is y, and the hypotenuse is r=1, so we can rewrite this equation as sin(50) = y/r = y Which means that y is simply sin(50). Similarly, cos(a) = adjacent/hypotenuse, so cos(50) = x/r = x. x = cos(50). P is therefore located at (cos[50], sin[50])
spelling :P //I GOOGLE MO :P
It's x = 0. Consider a point of the plane, P=(x, y), in cartesian coordinates. If P is a point belonging to x-axis, then P=(x, y=0); if P is a point belonging to y-axis, then P=(x=0, y).
Nothing happens. Or in other words, it just end like normal. And they kill a rat :P
Pythagoras was a person :P but I assume you talk about the formula: a^2+b^2=c^2, so if you took the square root of a^2+b^2, you would get c, probably the result you were looking for
what is the measurement in degrees of angle 7
55 - 20 = 35
The polarizing angle is the angle at which light is completely polarized when it reflects off a surface. The critical angle is the angle at which light is refracted along the surface when entering a different medium. These angles are related in that the polarizing angle can be calculated using the critical angle and the refractive indices of the two media involved.
if you read this you smell :p
<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
The answer will depend on the location of the points B, P and C.
90 degress :P
Di ko alam sagot salamat
Sum of all three angles is 180 degrees. p = 36 so q+r = 180-36 = 144 degrees. Now, q = 5r so 144 = q+r = 5r+r = 6r so r = 144/6 = 24 and then q = 5r = 5*24=120 Answer: q = 120 deg, r = 24 deg
go on tan cheat :P haha fooled you