Since 120 ends with zero, then 120 is divisible by 5.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
A multiple of 5 between 100 and 200 that is also divisible by both 4 and 6 is 120. It meets these criteria because 120 is a multiple of 5 (24 x 5 = 120), divisible by 4 (120 ÷ 4 = 30), and divisible by 6 (120 ÷ 6 = 20). Other multiples of 5 in that range, like 125 or 130, do not meet the divisibility requirements for 4 and 6.
Any number ending in 0 is always divisible by 5 and 2 (and more).
120 is one such number.
Yes, 120 is divisible by 2, 4, 5, 6, 8, and 10. This is because 120 is an even number, and it can be evenly divided by these factors without leaving a remainder. However, 120 is not divisible by 3 or 9, as dividing by these numbers does not yield a whole number.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
No, 120 is not the smallest number that is divisible by 1,2,3,4,5 and 6.
120 ÷ 5 = 24
A multiple of 5 between 100 and 200 that is also divisible by both 4 and 6 is 120. It meets these criteria because 120 is a multiple of 5 (24 x 5 = 120), divisible by 4 (120 ÷ 4 = 30), and divisible by 6 (120 ÷ 6 = 20). Other multiples of 5 in that range, like 125 or 130, do not meet the divisibility requirements for 4 and 6.
2, 5 and 10 are factors of 120 because they divide evenly into 120 with no remainder.
Any number ending in 0 is always divisible by 5 and 2 (and more).
120 is divisible by the following numbers: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120.
1
120
120
120 is one such number.